- #1
LagrangeEuler
- 717
- 20
Why this integral is called elliptic?
[tex]I(k)=\int^{\frac{\pi}{2}}_0(1-k^2\sin^2 \varphi)^{-\frac{1}{2}}d \varphi[/tex]
[tex]I(k)=\int^{\frac{\pi}{2}}_0(1-k^2\sin^2 \varphi)^{-\frac{1}{2}}d \varphi[/tex]