Elliptical Orbit Homework: Calculate r1/r0

In summary, the equation of the elliptical orbit of Earth around the sun is given by r=ep/1−e cosa, where p is some constant and e = 1/60. The nearest and the furthest distance of the Earth from the sun are denoted by r0 and r1, and r1/r0 is calculated. Cryphonus tried to give the max and min values for cosa, but wasn't sure if it was right. If you have calculus, you should be able to determine the critical angles for the orbit equation. The value of \cos a ranges between -1 and +1, and the minimum and maximum values for the denominator in the equation, r
  • #1
Cryphonus
60
0

Homework Statement



The equation of the elliptical orbit of Earth around the sun in
polar coordinates is given by
r =ep/1 − e cosa
where p is some positive constant and e = 1/60. Let r0 and r1
denote the nearest and the furthest distance of the Earth from
the sun. Calculate r1/r0

Homework Equations



the one that is provided with the question

The Attempt at a Solution



I simply tried to give the max and min values for Cosa, which is 90 and 0 degrees.But I am not really sure if its right,Glad if you can help me here...

Thanks a lot

Cryphonus
 
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  • #2
Cryphonus said:
I simply tried to give the max and min values for Cosa, which is 90 and 0 degrees.But I am not really sure if its right,Glad if you can help me here...
That's not right. Try drawing a picture with the Sun at one of the foci of the ellipse. For what angles does the distance between the Earth and Sun reach minimum and maximum?
 
  • #3
0 - 180 degrees?
 
  • #4
Don't guess!

Do you know calculus? If you do you should easily be able to determine these critical angles. Even without calculus, a bit of critical thinking is all that is needed. The value of [itex]\cos a[/itex] ranges between -1 and +1. Given that, what are the minimum and maximum values for the denominator in your equation, [itex]r=ep/(1-e\cos a)[/itex]? Finally, are the extrema in the denominator related to the extrema of the radial distance?

BTW, that equation does not look quite right. The orbit equation in standard form is [itex]r=p/(1+e\cos\theta)[/itex].
 
  • #5
I didnt guessed it :) .It just i took the max and min values as 0 and 1 which is ofcourse not true, so silly of me (: . I don't know about the equation it is given in the question.. but if you have any idea about what the question says "where p is some constant" i would be happy to hear.I never heard such a constant called "p" about this subject...
 
  • #6
One way to express the radial distance as a function of angle for an elliptical orbit is

[tex]r=\frac {a(1-e^2)}{1+e\cos \theta}[/tex]

where a is the semi-major axis, e is the eccentricity of the orbit, and θ is the "true anomaly", the angle between the line from the focus to the closest approach ("perifocus") and the line from the focus to the current position.

An alternative parameter to the semi-major axis a for characterizing the size of an ellipse is the semi-latus rectum, [itex]p=a(1-e^2)[/itex]. The semi-latus rectum is also given by

[tex]p=\frac{h^2}{GM}[/tex]

where h is the specific orbital angular momentum, G is the universal gravitational constant, and M is the mass of the central object (e.g., the Sun).

Note that there is no factor of e in either form of the orbit equation.
 
  • #7
Ok thanks a lot i will ask around in the collegea about e
 

FAQ: Elliptical Orbit Homework: Calculate r1/r0

1. What is an elliptical orbit?

An elliptical orbit is a type of orbit in which an object, like a planet or satellite, follows an elliptical path around another object, such as a star or planet. This means that the object's distance from the central object varies at different points in its orbit.

2. How is the ratio r1/r0 calculated for an elliptical orbit?

The ratio r1/r0, also known as the eccentricity, is calculated by dividing the distance between the two foci of the ellipse by the length of the major axis. The foci are the two fixed points within the ellipse, and the major axis is the longest diameter of the ellipse. This ratio gives information about the shape of the elliptical orbit.

3. Why is calculating r1/r0 important in understanding elliptical orbits?

Calculating r1/r0 is important because it helps us understand the shape and characteristics of an elliptical orbit. This ratio can tell us how elongated or circular the orbit is, and can also help us determine the object's speed and trajectory at different points in its orbit.

4. What factors affect the value of r1/r0 for an elliptical orbit?

The value of r1/r0, or eccentricity, is affected by the mass and velocity of the orbiting object, as well as the mass and distance of the central object. It can also be influenced by the presence of other objects in the surrounding space.

5. How is the ratio r1/r0 used in real-life applications?

The ratio r1/r0 is used in various real-life applications, such as predicting the orbits of planets and satellites, and in spacecraft trajectory planning. It is also used in astronomy to study the dynamics of celestial bodies and their interactions with each other.

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