- #1
Callisto
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If the emissivity e varies with zenith angle according to e = E*cos(theta) where E is the emissivity normal to the surface. Would this surface be an isotropic source of radiation?
Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate anistropically.
Anybody disagree?
Callisto
Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate anistropically.
Anybody disagree?
Callisto