Encountered a WEIRD vertex-form equation

  • Thread starter AznBoi
  • Start date
  • Tags
    Weird
In summary, the equation y=(x-1)^2 has a y-intercept of (0,1) because the y-intercept is always at the vertex, which is represented by the coordinates (p,q) in the vertex-form equation y=a(x-p)^2+q. The y-intercept is different from the x-intercept, which is represented by h in the equation. In the equation y=(x-2)^2+6, 2 is the x-intercept and 6 is the y-intercept.
  • #1
AznBoi
471
0
Ok the equation: y=(x-1)^2

How come it has a y intercept of (0,1) but the equation does not have a
+1 at the end of it??

I thought all y-intercepts are at the end of the vertex-form equation.
 
Physics news on Phys.org
  • #2
[tex] y = a(x-p)^{2} + q[/tex] where [tex] (p,q) [/tex] are the coordinates of the vertex. You are thinking of [tex] y=mx+b [/tex] where [tex] b [/tex] is the y-intercept.
 
  • #3
Lol, yeah that's it. So only the equation of the line has the y-intercept in it. The h,k is only the vertex, k is not the y-intercept right?
 
  • #4
k is the y-intercept, h is the x-intercent in the form [itex]y=a(x-h)^{2}+k[/itex]
 
  • #5
no its not. So if you have [tex] y = (x-2)^{2} + 6 [/tex] your saying 2 is the x-intercept, and 6 is the y-intercept?
 

FAQ: Encountered a WEIRD vertex-form equation

What is a vertex-form equation?

A vertex-form equation is a mathematical equation that represents a parabola in the form y = a(x-h)^2 + k, where (h,k) is the vertex of the parabola and a is a constant value that determines the direction and shape of the parabola.

How do I identify a vertex-form equation?

A vertex-form equation will always have the variables x and y, as well as the squared term (x-h)^2. The values of a, h, and k can also be identified from the equation.

What makes a vertex-form equation "weird"?

A vertex-form equation can be considered "weird" if the value of a is negative, which results in a downward facing parabola. This is because most people are accustomed to seeing parabolas with a positive value of a, which creates an upward facing parabola.

How do I graph a vertex-form equation?

To graph a vertex-form equation, you can plot the vertex point (h,k) on the coordinate plane and use the value of a to determine the direction and shape of the parabola. Then, you can plot other points on the parabola by substituting different values for x and solving for y.

Can a vertex-form equation have a vertex at the origin?

Yes, a vertex-form equation can have a vertex at the origin if the values of h and k are both 0. This results in an equation in the form y = ax^2, which is a basic parabola with a positive value of a.

Similar threads

Replies
6
Views
1K
Replies
6
Views
865
Replies
8
Views
1K
Replies
12
Views
2K
Replies
3
Views
993
Back
Top