- #1
LCSphysicist
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- 162
- Homework Statement
- I will put it below.
- Relevant Equations
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How do the energy and generalized momenta change under the following coordinate
transformation $$q= f(Q,t)$$The generalized momenta: $$P = \partial L / \partial \dot Q = \partial L / \partial \dot q\times \partial \dot q / \partial \dot Q = p \partial \dot q / \partial \dot Q = p \partial q / \partial Q $$$$\dot Q = \partial Q / \partial q \times \dot q + \partial Q / \partial t$$$$E' = P\dot Q - L = p \partial q / \partial Q (\partial Q / \partial q \times \dot q + \partial Q / \partial t) - L = p\dot q + p \partial q / \partial t - L = E + p \partial q / \partial t$$But the answer is $$E' = E - p \partial q / \partial t$$What did i got wrong?
transformation $$q= f(Q,t)$$The generalized momenta: $$P = \partial L / \partial \dot Q = \partial L / \partial \dot q\times \partial \dot q / \partial \dot Q = p \partial \dot q / \partial \dot Q = p \partial q / \partial Q $$$$\dot Q = \partial Q / \partial q \times \dot q + \partial Q / \partial t$$$$E' = P\dot Q - L = p \partial q / \partial Q (\partial Q / \partial q \times \dot q + \partial Q / \partial t) - L = p\dot q + p \partial q / \partial t - L = E + p \partial q / \partial t$$But the answer is $$E' = E - p \partial q / \partial t$$What did i got wrong?