- #1
p75213
- 96
- 0
Given that:
E = hν where
E = energy of a photon
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
Why is it that the energy (electromagnetic waves) in AC electrical circuits does not include frequency as part of the formula? eg.
[tex]\begin{array}{l}
P = \frac{1}{2}{V_m}{I_m}\varphi \to \omega = \int_0^t {P\,dt} \\
{\rm{Where: }} \\
{\rm{P = average power, }} \\
{V_m} = {\rm{voltage magnitude, }} \\
{I_m}{\rm{ = current magnitude, }} \\
\omega = {\rm{energy, }} \\
\varphi {\rm{ = power factor(}}\cos ({\theta _v} - {\theta _i})) \\
\end{array}[/tex]
The same thing applies to the formula for the energy contained in an inductor:
[tex]\begin{array}{l}
\omega = \frac{1}{2}L{i^2} \\
{\rm{Where:}} \\
L{\rm{ = inductance}} \\
i{\rm{ = current}} \\
\end{array}[/tex]
E = hν where
E = energy of a photon
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
Why is it that the energy (electromagnetic waves) in AC electrical circuits does not include frequency as part of the formula? eg.
[tex]\begin{array}{l}
P = \frac{1}{2}{V_m}{I_m}\varphi \to \omega = \int_0^t {P\,dt} \\
{\rm{Where: }} \\
{\rm{P = average power, }} \\
{V_m} = {\rm{voltage magnitude, }} \\
{I_m}{\rm{ = current magnitude, }} \\
\omega = {\rm{energy, }} \\
\varphi {\rm{ = power factor(}}\cos ({\theta _v} - {\theta _i})) \\
\end{array}[/tex]
The same thing applies to the formula for the energy contained in an inductor:
[tex]\begin{array}{l}
\omega = \frac{1}{2}L{i^2} \\
{\rm{Where:}} \\
L{\rm{ = inductance}} \\
i{\rm{ = current}} \\
\end{array}[/tex]