Energy of a water tank with compressed air

  • #1
davidpele
4
0
Homework Statement
Lets fill a 1m x 1m x 2m enclosed water tank with 1m3 of water. Lets place the tank at sea level resulting in the tank having 1 atm of pressure. Now lets pump air into the tank until it is at 2 atm. Has the tanks potential energy changed and by how much?
Relevant Equations
mgh
At sealevel, the water in the tank is just mgh so 1000 kg * g * 1m so about 10 kjoules.
Now if we pump air until it is 2 atm.

The potential energy of a compressed gas is given by the formula:
U = -nRTln(V2/V1)

But in this case it is not the gas that we care about but the water.

I can understand that the tank has higher potential energy because of the higher pressure inside it. But I can't figure out how to calculate how much it has changed by.

I can imagine increasing the air pressure is like lowering it in height. 10m deep in the sea is the equivalent of 2atm.

The other way I can think of this is like the compressed air is raising the height of the tank.
The energy required to compress 1 m³ of air at 1 atm and 25°C to 2 atm is approximately 2,436 J.
So that would mean we've supplied 2436 joules of potential energy to the water.

So the change in height would h = 2436/1000g around 25cm.

Am I thinking about this in reasonable way?

Thanks.
 
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  • #2
davidpele said:
Homework Statement: Lets fill a 1m x 1m x 2m enclosed water tank with 1m3 of water. Lets place the tank at sea level resulting in the tank having 1 atm of pressure. Now lets pump air into the tank until it is at 2 atm. Has the tanks potential energy changed and by how much?
Relevant Equations: mgh

At sealevel, the water in the tank is just mgh so 1000 kg * g * 1m so about 10 kjoules.
Now if we pump air until it is 2 atm.

The potential energy of a compressed gas is given by the formula:
U = -nRTln(V2/V1)

But in this case it is not the gas that we care about but the water.

I can understand that the tank has higher potential energy because of the higher pressure inside it. But I can't figure out how to calculate how much it has changed by.

I can imagine increasing the air pressure is like lowering it in height. 10m deep in the sea is the equivalent of 2atm.

The other way I can think of this is like the compressed air is raising the height of the tank.
The energy required to compress 1 m³ of air at 1 atm and 25°C to 2 atm is approximately 2,436 J.
So that would mean we've supplied 2436 joules of potential energy to the water.

So the change in height would h = 2436/1000g around 25cm.

Am I thinking about this in reasonable way?

Thanks.
No. Are you talking about gravitational potential energy or some other kind of potential energy? Can you please provide a schematic of the system you are describing?
 
  • #3
Chestermiller said:
No. Are you talking about gravitational potential energy or some other kind of potential energy? Can you please provide a schematic of the system you are describing?
Thanks for your reply. I realized I missed one important contextual thing. The way to measure the "energy" present in that system would be to put the water through a turbine and measure the amount of energy generated. I guess that means gravitational potential energy plus the additional energy due to air in the tank being at 2 atm thus exerting additional pressure on the water and increasing the amount of energy it could generate through the turbine.
 
  • #4
davidpele said:
Thanks for your reply. I realized I missed one important contextual thing. The way to measure the "energy" present in that system would be to put the water through a turbine and measure the amount of energy generated. I guess that means gravitational potential energy plus the additional energy due to air in the tank being at 2 atm thus exerting additional pressure on the water and increasing the amount of energy it could generate through the turbine.
Please show how you would set this up schematically in terms of piping and turbine. Why do you feel you need to put a number on this?
 
  • #5
I'm sorry, I don't think I understand what you mean by schematically. Could you give an example? The question is interesting to me and hopefully to others. Thanks for the discussion.
 
  • #6
I found this diagram of an airbattery. This looks like a good example.
 

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Related to Energy of a water tank with compressed air

What is the principle behind using compressed air to store energy in a water tank?

The principle involves using compressed air to pressurize water in a tank. When energy is needed, the pressurized air forces the water through a turbine or generator, converting the potential energy stored in the compressed air and water into electrical energy.

How efficient is the energy storage in a water tank with compressed air?

The efficiency of such a system can vary, but it is generally lower compared to other energy storage methods like batteries or pumped hydro. Typical efficiencies range from 40% to 70%, depending on the system design and operational conditions.

What are the main components of a water tank with compressed air energy storage system?

The main components include a water tank, an air compressor, a turbine or generator, pressure regulation equipment, and control systems. The water tank stores the water, while the air compressor pressurizes the air. The turbine or generator converts the energy into electricity, and the control systems manage the operation.

What are the advantages of using a water tank with compressed air for energy storage?

Advantages include relatively low cost, scalability, and the use of abundant and non-toxic materials like water and air. Additionally, such systems can be integrated with renewable energy sources to provide a steady supply of electricity.

What are the challenges or limitations of this energy storage method?

Challenges include lower efficiency compared to other storage methods, potential energy losses due to heat dissipation, and the need for large storage volumes to achieve significant energy storage capacity. Additionally, maintaining the integrity of the pressure vessel over time can be a concern.

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