- #1
nishantve1
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Homework Statement
What is the energy of H atom in the first excited state if the potential energy in the ground state is taken to be 0 ?
Homework Equations
Usually the energy of H atom in the ground state is -13.6eV
and in the 1st excited state is -10.2eV
E(n) = πme2/8ε2h2
Bohr's radius = 0.529 angstrom
The answer provided is : 23.8eV
The Attempt at a Solution
So I went with how the energy of the electron is derived from ground up
Knowing that
Total energy = potential energy + Kinetic energy
potential energy due to the positive charge on nucleus and negative on electron
so if the potential energy is taken to be 0 then the only energy left is the kinetic one so
the energy would just be
1/2 mvv
then I substituted
v = e2/2∏hn
then I used the formula
ΔE = 13.6(3/4)
but everything is now messed up and I ended up with a gross looking equation , I know something doesn't makes sense above may be nothing does .
Thanks in advance :
P.S : the answer is 23.8 and 13.6 + 10.2 = 23.8
but how can I possibly do this ?