- #1
Bhope69199
- 42
- 3
Hi,
When calculating the energy of an ideal gas we neglect the potential energy and calculate the kinetic energy using:
K.E = 3 /2 n R T
My question is why do we not consider the electrostatic energy of the gas?
If I am trying to work out the internal energy of 1 mol of Radon, why do I only require the kinetic energy and not the energy that was required to bring the electrons and protons together? Is this energy not held within the gas?
When calculating the energy of an ideal gas we neglect the potential energy and calculate the kinetic energy using:
K.E = 3 /2 n R T
My question is why do we not consider the electrostatic energy of the gas?
If I am trying to work out the internal energy of 1 mol of Radon, why do I only require the kinetic energy and not the energy that was required to bring the electrons and protons together? Is this energy not held within the gas?