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Homework Statement
An elevator is traveling at 30 m/s just as it touches a cushioning spring. The safety clamps engage at that moment and provide 20,000N of frictional force. The mass of the elevator is 3000kg and the spring constant is 15000 N/m. How fast will the elevator be traveling after the spring compresses 0.8m ?
Homework Equations
K1+Wf = Ug2+Us2+K2
Allow the point that the elevator touches the spring to be y=0
The Attempt at a Solution
1/2*m(v1)2+Ffd=mgy2+1/2*kx2+1/2*mv22
Manipulating this around and plugging in numbers gives an answer of 30.03 m/s for me. Am I missing something here?
Edit: d is just the distance along which friction occurs, -.8 m?
x is the compression of the spring, also .8m
y2 is the distance traveled by the elevator, so -.8m
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