- #1
eliassiguenza
- 24
- 0
1. Homework Statement
a beaker contains 200mL of ethyl alcohol at 22 C degrees. what is the minumum amount of energy that must be removed to produce solid ethyl alcohol..
the melting/freezing pt is -114 C degrees
Latent heat fusion = 1.09x10^5
density is 790kg/m^3
specific heat capacity = 2400 J/kg * K
2. Homework Equations
Q=mcdT
Q=ML
m=pv
Qtotal = Q1 + Q2 (Q1 = m c dT + Q=ML)
3. The Attempt at a Solution
m= p * v = (2.00*10^-4m^3)(790)=0.1578kg
so..
Q=0.1578 (2400) (136)
=51505.92 J
Q2 = 0.1578 (1.09*10^5)
=17200.2
Q1 + Q2 = 68706.12
Apparently I'm wrong where have i made a mistake! =( I'm very frustrated...
a beaker contains 200mL of ethyl alcohol at 22 C degrees. what is the minumum amount of energy that must be removed to produce solid ethyl alcohol..
the melting/freezing pt is -114 C degrees
Latent heat fusion = 1.09x10^5
density is 790kg/m^3
specific heat capacity = 2400 J/kg * K
2. Homework Equations
Q=mcdT
Q=ML
m=pv
Qtotal = Q1 + Q2 (Q1 = m c dT + Q=ML)
3. The Attempt at a Solution
m= p * v = (2.00*10^-4m^3)(790)=0.1578kg
so..
Q=0.1578 (2400) (136)
=51505.92 J
Q2 = 0.1578 (1.09*10^5)
=17200.2
Q1 + Q2 = 68706.12
Apparently I'm wrong where have i made a mistake! =( I'm very frustrated...