Enthalpy of Formation of Carbon Monoxide

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To calculate the enthalpy of formation for carbon monoxide (CO), the user suggests reversing the second reaction to obtain CO from CO2, resulting in a positive enthalpy change of +283 kJ mol-1. They seek clarification on whether to substitute this value into the first equation involving carbon dioxide (CO2) and how to combine the equations correctly. The goal is to manipulate the provided equations to derive the enthalpy change for the formation of CO from its elements. The discussion focuses on the steps needed to achieve the desired calculation. Further guidance on combining the equations is requested.
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Homework Statement


Using the information provided for energy changes associated with the formation
of carbon dioxide, calculate the enthalpy for the formation of carbon monoxide.

C(gr) + O2(g) → CO2(g) ΔH (-393.5 kJ mol-1)
CO(g) + ½ O2 (g) → CO2 (g) ΔH (-283 kJ mol -1)
C(gr) + ½ O2 (g) → CO(g) ΔH = ?


Homework Equations


None really.


The Attempt at a Solution


Reverse equation #2 to get CO2 (g) → CO(g) + ½ O2 (g) (+283 kJ mol -1). I think that's one of the steps anyway. Haven't done of these in ages. Do I sub in for CO2 in equation #1 and then add the enthalpy of formations? What's the next step?
 
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Combine first two equations in such a way they yield third.
 
Thanks for that.
 

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