- #1
krbs
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Homework Statement
An alpha particle moving at 3.0 x 106 m/s [east] (m2 = 6.64 x 10-27 kg and q2 = +3.2 x 10-19 C) is headed directly towards a proton moving at 5.0 x 106 m/s [west] (m1 = 1.67 x 10-27 kg, q1 = 1.6 x 10-19 C). Find the distance of closest approach, assuming that they start from a very far apart position.
Homework Equations
Ek + Ek = EE
The Attempt at a Solution
##0.5(6.64 \times 10^{-27}kg)(3.0 \times 10{^6} m/s)^2\ +\ (0.5)(1.67 \times 10^{-27}kg)(-5.0 \times 10^6m/s)^2\ =\ \frac{(9.0\times10^9)(3.2 \times 10^{-19}C)(1.6\times10^{-19}C)}{r}\\
r\ =\ \frac{(9.0\times10^9)(3.2 \times 10^{-19}C)(1.6\times10^{-19}C)}{0.5(6.64 \times 10^{-27}kg)(3.0 \times 10{^6} m/s)^2\ +\ (0.5)(1.67 \times 10^{-27}kg)(-5.0 \times 10^6m/s)^2}\\
r\ =\ 9.1\times10^{-15}##