- #1
Mathman23
- 254
- 0
Hi
I got two questions:
1] A equality reaction:
[itex]\mathrm{2N + O_{2} \rightleftharpoons 2NO}[/itex]
a) How does one remove NO from the reaction?
2] An equality mixture [itex] \mathrm{H_2 + Br_2 \rightleftharpoons 2 HBr}[/itex]
contains 0,340 mol [itex]H_2[/itex] , 0,220 mol [itex]\mathrm{Br_2}[/itex].
in a canister which has a volume V = 1,0 L.
The mixture is heated to reaches a tempeture of 700K.
Then the reaction has set itself 0,0196 mol is left of [itex]Br_{2}[/itex]
a) The concentration of [itex]\mathrm{C_{H_2} = \frac{0,34 mol}{1,0 L} = 0,34 mol/L}[/itex]
The concentration of [itex]\mathrm{C_{Br_2} = \frac{0,22 mol}{1,0 L} = 0,22 mol/L}[/itex]
b) The equality fraction for the reaction is: [itex]\mathrm{K_c} = \frac{\mathrm{[HBr]^2}}{\mathrm{[H_2] \cdot [Br_2]}}[/itex]
c) How do I obtain [HBr] ?
Sincerely
/Fred
I got two questions:
1] A equality reaction:
[itex]\mathrm{2N + O_{2} \rightleftharpoons 2NO}[/itex]
a) How does one remove NO from the reaction?
2] An equality mixture [itex] \mathrm{H_2 + Br_2 \rightleftharpoons 2 HBr}[/itex]
contains 0,340 mol [itex]H_2[/itex] , 0,220 mol [itex]\mathrm{Br_2}[/itex].
in a canister which has a volume V = 1,0 L.
The mixture is heated to reaches a tempeture of 700K.
Then the reaction has set itself 0,0196 mol is left of [itex]Br_{2}[/itex]
a) The concentration of [itex]\mathrm{C_{H_2} = \frac{0,34 mol}{1,0 L} = 0,34 mol/L}[/itex]
The concentration of [itex]\mathrm{C_{Br_2} = \frac{0,22 mol}{1,0 L} = 0,22 mol/L}[/itex]
b) The equality fraction for the reaction is: [itex]\mathrm{K_c} = \frac{\mathrm{[HBr]^2}}{\mathrm{[H_2] \cdot [Br_2]}}[/itex]
c) How do I obtain [HBr] ?
Sincerely
/Fred