- #1
ur5pointos2sl
- 96
- 0
Find an equation for the tangent to the curve at the given point.
y=2(sqrt(x)) point- (1,2)
Ok so I think I can work most of it then I get stuck. I am not sure how you guys use the codes so I will try to type it out the best I can.
lim = ( f(a+h)-f(a) ) / (h)
h->0
= f(1+h)-f(1) / h
= (2 sqrt(1+h) - 2) / h
This is where I have gotten to. substituting in now will give me a 0 in my denominator. So where would I go next?
y=2(sqrt(x)) point- (1,2)
Ok so I think I can work most of it then I get stuck. I am not sure how you guys use the codes so I will try to type it out the best I can.
lim = ( f(a+h)-f(a) ) / (h)
h->0
= f(1+h)-f(1) / h
= (2 sqrt(1+h) - 2) / h
This is where I have gotten to. substituting in now will give me a 0 in my denominator. So where would I go next?