- #1
Whiz
- 20
- 0
Homework Statement
Find an equation for the plane containing the lines:
x-3= 4t , y-4 = t, z-1 = 0
x+1 = 12t, y-7 = 6t, z-5 = 3t
The Attempt at a Solution
I found the equations of both lines.
First line:
(3, 4, 1) + t(4, 1, 0)
(-1, 7, 5) + t(12, 6, 3)
Now I take the cross product of (4, 1, 0) and (12, 6, 3) to get (3, -12, 12)
I found two answers from reviewing this question and I'm confusing myself, so I was wondering which answer is right. (If any)
3x - 12y + 12z = 27
or
3x - 12y + 12z = 0
Thanks in advance.