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thorpelizts
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Find the equation of the circle whose centre is (-3,4) and which touches the y-axis.
how do i even begin?
how do i even begin?
Teacher gave no instructions, no teaching?thorpelizts said:Find the equation of the circle whose centre is (-3,4) and which touches the y-axis.
how do i even begin?
thorpelizts said:Find the equation of the circle whose centre is (-3,4) and which touches the y-axis.
how do i even begin?
Find the equation of the circle whose centre is (-3,4) and which touches the y-axis.
How do i even begin? . Make a sketch!
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* (-3,4) *
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thorpelizts said:Find the equation of the circle whose centre is (-3,4) and which touches the y-axis.
how do i even begin?
The equation of a circle centered at (-3,4) that touches the y-axis can be written as (x+3)^2 + (y-4)^2 = r^2, where r is the radius of the circle.
The radius of the circle can be found by calculating the distance between the center (-3,4) and any point on the circle that touches the y-axis. This distance will be equal to the radius of the circle.
No, a circle can only touch the y-axis at one point if it is centered at (-3,4). This is because the distance from the center to any point on the circle must be equal to the radius of the circle, and there is only one point on the y-axis that is at a specific distance from the center.
The value of r, or the radius, directly affects the size of the circle centered at (-3,4) that touches the y-axis. A larger value of r will result in a larger circle, while a smaller value of r will result in a smaller circle.
Yes, the equation of a circle centered at (-3,4) that touches the y-axis can also be written as (x+3)^2 + (y-k)^2 = k^2, where k is the distance between the center and the y-axis. This form may be more convenient when finding the radius or graphing the circle.