Equation of Circle Through Origin

In summary, the equation of a circle passing through the origin with center (3, 5) is (x - 3)^2 + (y - 5)^2 = 34. The radius can be found by taking the square root of the sum of the squares of the difference between the center and the given point. This is an essential concept to understand before moving on to calculus.
  • #1
mathdad
1,283
1
Find the equation of the circle passing through the origin with center (3, 5).

Can someone get me started? Must I use the point (0, 0) here?
 
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  • #2
RTCNTC said:
Find the equation of the circle passing through the origin with center (3, 5).

Can someone get me started? Must I use the point (0, 0) here?

If the center of the circle is at (3, 5) and one of the points on the circle is (0, 0), then how can we find the radius of the circle? In a circle, just what is the radius? How it is defined?
 
  • #3
MarkFL said:
If the center of the circle is at (3, 5) and one of the points on the circle is (0, 0), then how can we find the radius of the circle? In a circle, just what is the radius? How it is defined?

The radius is the distance between the origin and given point.
 
  • #4
RTCNTC said:
The radius is the distance between the origin and given point.

The radius is the distance between the center of the circle and any point on the circle. Since we are given the center and a point on the circle, we can determine the radius. :D
 
  • #5
MarkFL said:
The radius is the distance between the center of the circle and any point on the circle. Since we are given the center and a point on the circle, we can determine the radius. :D

Let r = radius

r = sqrt{(3 - 0)^2 + (5 - 0)^2}

r = sqrt{3^2 + 5^2}

r = sqrt{9 + 25}

r = sqrt{34}

- - - Updated - - -

(x - h)^2 + (y - k)^2 = r^2

(x - 3)^2 + (y - 5)^3 = (sqrt{34})^2

(x - 3)^2 + (y - 5)^2 = 34

Correct?
 
  • #6
Looks good to me. (Yes)
 
  • #7
Instead of posting every question in the David Cohen precalculus textbook, I will post essential questions, questions that every student should know how to solve before going to calculus 1. There is no time to waste.
 

FAQ: Equation of Circle Through Origin

What is the equation of a circle through the origin?

The equation of a circle through the origin is x² + y² = r², where r is the radius of the circle. This equation is derived from the Pythagorean theorem, where the distance from any point on the circle to the origin is equal to the radius.

How do you know if a circle passes through the origin?

A circle passes through the origin if the coordinates of the center point are (0,0) and the radius is greater than 0. This means that the equation of the circle will be x² + y² = r², where r is the radius. If the equation does not have the form of x² + y² = r², then the circle does not pass through the origin.

What is the significance of the origin in the equation of a circle?

The origin is significant in the equation of a circle because it serves as the center point of the circle. This means that all points on the circle are equidistant from the origin, and the distance from any point on the circle to the origin is equal to the radius of the circle.

Can a circle through the origin have a negative radius?

No, a circle through the origin cannot have a negative radius. The radius of a circle represents the distance from the center point to any point on the circle, and distance cannot be negative. Therefore, the radius of a circle through the origin must always be a positive value.

How do you graph a circle through the origin?

To graph a circle through the origin, plot the center point at (0,0) and then use the radius to plot points around the origin. You can also use the equation x² + y² = r² to find other points on the circle by substituting different values for x and solving for y, or vice versa. Once you have several points, you can connect them to create a smooth circle.

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