Equation of hyperbola confocal with ellipse having same principal axes

  • #1
Aurelius120
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Homework Statement
If the ellipse $$4x^2+9y^2+12x+12y+5=0$$ is confocal with a hyperbola having same principal axes then:
Relevant Equations
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The equation of ellipse reduces to :
$$(2x+3)^2+(3y+2)^2=8$$
$$\frac{(x+3/2)^2}{8/4}+\frac{(y+2/3)^2}{8/9}=1$$

Center of ellipse =##\left(\frac{-3}{2},\frac{-2}{3}\right)##

##b^2=a^2(1-e^2)=8/9## and ##a^2=8/4##
Therefore ##e=\frac{\sqrt{5}}{3}##

Distance between foci=##\frac{2\sqrt{10}}{3}##
Length of latus rectum of ellipse is 2 times the value of ##y## obtained on putting ##x=ae## and is equal to ##\frac{8\sqrt{2}}{9}##
Now comes the difficult part :
Finding the equation of hyperbola. I simply can't seem to do it.

For confocal hyperbola,
$$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\text{ and } ae=\frac{\sqrt{10}}{3}$$.
If principal axes have same length they become the same curve so I think principal axes are unequal in length but coincident.

I don't know what to do next ? I think there's insufficient information to get the equation of hyperbola.
 
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  • #2
Also just to clarify more than one options are correct so all need to be checked
 
  • #3
The question does not imply there is a unique hyperbola meeting those conditions. The question is whether every such hyperbola satisfies A and D.
 
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  • #4
haruspex said:
The question does not imply there is a unique hyperbola meeting those conditions. The question is whether every such hyperbola satisfies A and D.
So without knowing the equation of hyperbol, how can A and D be verified?
 

FAQ: Equation of hyperbola confocal with ellipse having same principal axes

What is the general equation of a hyperbola confocal with an ellipse?

The general equation of a hyperbola confocal with an ellipse having the same principal axes can be expressed as: \[(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1)\]where \(a\) is the semi-major axis and \(b\) is the semi-minor axis of the ellipse. The hyperbola opens along the x-axis when \(a > b\).

How do you derive the equation of a hyperbola from the ellipse?

To derive the equation of a hyperbola from an ellipse, you start with the standard form of the ellipse:\[(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1).\]By substituting \(= 1\) with \(-1\) for the hyperbola, you get:\[(\frac{x^2}{a^2} - \frac{y^2}{b^2} = -1).\]Multiplying through by \(-1\) leads to the standard form of the hyperbola equation.

What are the properties of a hyperbola confocal with an ellipse?

A hyperbola confocal with an ellipse shares several properties, including:1. Both conics share the same foci.2. The transverse axis of the hyperbola is aligned with the major axis of the ellipse.3. The distance between the foci of the hyperbola is greater than that of the ellipse.4. The asymptotes of the hyperbola can be derived from the equation and are given by the lines \(y = \pm \frac{b}{a}x\).

How do the foci of a hyperbola compare to those of an ellipse?

For both ellipses and hyperbolas, the distance to the foci from the center is determined by the formula \(c^2 = a^2 + b^2\) for an ellipse, and \(c^2 = a^2 - b^2\) for a hyperbola. In the case of a hyperbola, the foci are located outside the vertices, whereas for an ellipse, the foci are inside the vertices. Thus, the hyperbola has a larger distance \(c\) than the corresponding ellipse.

Can you explain the relationship between the semi-major and semi-minor axes in a hyperbola?

In a hyperbola, the semi-major axis \(a\) and the semi-minor axis \(b\) have a specific relationship defined by the equation \(c^2 = a^2 + b^2\), where \(c\)

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