Equations for tangent & normal at P2 of circle P1 P2 P3?

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To find the tangent and normal at point P2 on a circle defined by points P1, P2, and P3, first determine the center of the circle by constructing the perpendicular bisectors of the lines connecting the points, which will intersect at the center. The line from the center to P2 is the normal to the circle at that point. To find the tangent, construct a line perpendicular to the normal at P2. This method provides a clear approach to deriving the necessary equations for the tangent and normal lines at the specified point.
CosmicVoyager
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Greetings,

Given three points P1 P2 P3 on a circle in x,y,z coordinates, I am trying to figure out how to get the tangent and normal at P2.

Anyone?

Thanks
 
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Hi CosmicVoyager! :smile:

Well, that means you first need to find the centre of the circle …

what lines do you think that will be on? :wink:
 
tiny-tim said:
Hi CosmicVoyager! :smile:

Well, that means you first need to find the centre of the circle …

what lines do you think that will be on? :wink:

The center of the circle won't be on any of the lines between the points. It is opposite the their normals?
 
If you construct the perpendicular bisectors of the lines between the points, they will intersect at the center of the circle.

Once you know that, construct the line from that center to each point. That line itself will be normal to the circle at the point. Constructing the line perpendicular to that line at the point gives you the tangent to the circle at that point.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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