Equilibrium heat equation in 2D cylindrical coordinates

In summary, the problem involves a plate with a circular halo shape and different temperatures at the inner and outer edges. By using Laplace's equation and separation of variables, two solutions are obtained: one for non-zero values of lambda and one for lambda=0. The general solution is a superposition of these two solutions. To find the unknown coefficients, the same procedure used for a string can be applied, by multiplying the solution by sine and cosine functions and using equations for the coefficients at the inner and outer edges.
  • #1
dingo_d
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Homework Statement


Plate in the shape of the circular halo (inner radius a, outer radius b>a), the inner edge is being kept at a constant temperature [tex]T_0[/tex], and the outer at the temperature given by the function [tex]f(\phi)=T_0\cos(2\phi)[/tex]. Find the equilibrium distribution of the heat everywhere inside the plate.

Homework Equations


Laplace equation:

[tex]\nabla^2 u(r,\phi)=0[/tex]

Boundary conditions:
[tex]u(a,\phi)=T_0[/tex]
[tex]u(b,\phi)=T_0\cos(2\phi)[/tex]

The Attempt at a Solution



By separation of variables I get:

[tex]r^2\frac{R''}{R}+r\frac{R'}{R}=-\frac{\Phi''}{\Phi}=\lambda^2[/tex]

For [tex]\lambda\neq 0[/tex] I have 2 DE, one is Euler's DE, and the other the equation of harmonic oscillator. Their solution is:

[tex]R(r)=Ar^\lambda+Br^{-\lambda}[/tex]

[tex]\Phi(\phi)=C\cos(\lambda\phi)+D\sin(\lambda\phi)[/tex]

With the condition of consistency of the azimuthal part:

[tex]\Phi(\phi)=\Phi(\phi+2\pi)[/tex]

I get that [tex]\lambda=m\in\mathbb{Z}[/tex], the [tex]\lambda=0[/tex] gives different solutions.

So my first solution is:

[tex]u_1(r,\phi)=\sum_{m=1}^\infty r^m[A_m\cos(m\phi)+B_m\sin(m\phi)]+\sum_{m=1}^\infty r^{-m}[C_m\cos(m\phi)+D_m\sin(m\phi)][/tex]

For [tex]\lambda=0[/tex] I have these solutions:

[tex]R(r)=C_0\ln(r)+D_0[/tex]

[tex]\Phi(\phi)=A_0\phi+B_0[/tex]

With the condition of consistency I get:

[tex]A_0\phi+B_0=A_0\phi+A_02\pi+B_0\Rightarrow A_0=0[/tex]

So the second solution is: (I have put the constants together)

[tex]u_2(r\phi)=C\ln(r)+D[/tex]

The general solution is the superposition of the two solutions:

[tex]u(r,\phi)=C\ln(r)+D+\sum_{m=1}^\infty r^m[A_m\cos(m\phi)+B_m\sin(m\phi)]+\sum_{m=1}^\infty r^{-m}[C_m\cos(m\phi)+D_m\sin(m\phi)][/tex]

So here is where my problem starts. I know that I'm supposed to use formulas for Fourier summation but in the case of a string that was the more straightforward, for example:

[tex]f(x,0)=\sum_{m=0}^\infty A_m\sin\left(\frac{m\pi}{L}x\right)\Big/ \cdot \sin\left(\frac{n\pi}{L}x\right),\ \int_0^L dx[/tex]

And the integral on the right would give me Kronecker delta which would 'kill' the sum so I would get the [tex]A_n[/tex] from that. But here I don't have this simple way. How should I get the [tex]A_m,\ B_m,\ C_m,\ D_m[/tex]?
 
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  • #2
dingo_d said:
I know that I'm supposed to use formulas for Fourier summation but in the case of a string that was the more straightforward, for example:

[tex]f(x,0)=\sum_{m=0}^\infty A_m\sin\left(\frac{m\pi}{L}x\right)\Big/ \cdot \sin\left(\frac{n\pi}{L}x\right),\ \int_0^L dx[/tex]

And the integral on the right would give me Kronecker delta which would 'kill' the sum so I would get the [tex]A_n[/tex] from that.

Use the same procedure for [tex] r=a [/tex] and [tex] r=b [/tex], multiplying your solution by [tex] sin(n\phi) [/tex] and [tex] cos(n\phi) [/tex]. You will get equations for the unknown coefficients.
 

FAQ: Equilibrium heat equation in 2D cylindrical coordinates

1. What is the equilibrium heat equation in 2D cylindrical coordinates?

The equilibrium heat equation in 2D cylindrical coordinates is a mathematical representation of the flow of heat in a cylindrical system. It takes into account the temperature distribution, thermal conductivity, and heat generation within the system to determine the steady-state temperature profile.

2. How is the equilibrium heat equation derived in 2D cylindrical coordinates?

The equilibrium heat equation in 2D cylindrical coordinates is derived from the fundamental laws of thermodynamics, specifically the heat diffusion equation. It takes into account the cylindrical geometry of the system and uses the Laplace operator to calculate the temperature distribution in the steady state.

3. What are the boundary conditions for the equilibrium heat equation in 2D cylindrical coordinates?

The boundary conditions for the equilibrium heat equation in 2D cylindrical coordinates depend on the specific system being studied. Generally, they include the temperature at the boundaries, the heat flux at the boundaries, and any sources or sinks of heat within the system.

4. Can the equilibrium heat equation in 2D cylindrical coordinates be solved analytically?

In some cases, the equilibrium heat equation in 2D cylindrical coordinates can be solved analytically, using techniques such as separation of variables or Fourier series. However, in more complex systems, numerical methods may be necessary to obtain a solution.

5. How is the equilibrium heat equation in 2D cylindrical coordinates used in practical applications?

The equilibrium heat equation in 2D cylindrical coordinates has many practical applications, such as in the design of heat exchangers, thermal insulation, and industrial processes. It is also used in the study of heat transfer in fluids, such as in the cooling of nuclear reactors or in the Earth's mantle.

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