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dingo_d
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Homework Statement
Plate in the shape of the circular halo (inner radius a, outer radius b>a), the inner edge is being kept at a constant temperature [tex]T_0[/tex], and the outer at the temperature given by the function [tex]f(\phi)=T_0\cos(2\phi)[/tex]. Find the equilibrium distribution of the heat everywhere inside the plate.
Homework Equations
Laplace equation:
[tex]\nabla^2 u(r,\phi)=0[/tex]
Boundary conditions:
[tex]u(a,\phi)=T_0[/tex]
[tex]u(b,\phi)=T_0\cos(2\phi)[/tex]
The Attempt at a Solution
By separation of variables I get:
[tex]r^2\frac{R''}{R}+r\frac{R'}{R}=-\frac{\Phi''}{\Phi}=\lambda^2[/tex]
For [tex]\lambda\neq 0[/tex] I have 2 DE, one is Euler's DE, and the other the equation of harmonic oscillator. Their solution is:
[tex]R(r)=Ar^\lambda+Br^{-\lambda}[/tex]
[tex]\Phi(\phi)=C\cos(\lambda\phi)+D\sin(\lambda\phi)[/tex]
With the condition of consistency of the azimuthal part:
[tex]\Phi(\phi)=\Phi(\phi+2\pi)[/tex]
I get that [tex]\lambda=m\in\mathbb{Z}[/tex], the [tex]\lambda=0[/tex] gives different solutions.
So my first solution is:
[tex]u_1(r,\phi)=\sum_{m=1}^\infty r^m[A_m\cos(m\phi)+B_m\sin(m\phi)]+\sum_{m=1}^\infty r^{-m}[C_m\cos(m\phi)+D_m\sin(m\phi)][/tex]
For [tex]\lambda=0[/tex] I have these solutions:
[tex]R(r)=C_0\ln(r)+D_0[/tex]
[tex]\Phi(\phi)=A_0\phi+B_0[/tex]
With the condition of consistency I get:
[tex]A_0\phi+B_0=A_0\phi+A_02\pi+B_0\Rightarrow A_0=0[/tex]
So the second solution is: (I have put the constants together)
[tex]u_2(r\phi)=C\ln(r)+D[/tex]
The general solution is the superposition of the two solutions:
[tex]u(r,\phi)=C\ln(r)+D+\sum_{m=1}^\infty r^m[A_m\cos(m\phi)+B_m\sin(m\phi)]+\sum_{m=1}^\infty r^{-m}[C_m\cos(m\phi)+D_m\sin(m\phi)][/tex]
So here is where my problem starts. I know that I'm supposed to use formulas for Fourier summation but in the case of a string that was the more straightforward, for example:
[tex]f(x,0)=\sum_{m=0}^\infty A_m\sin\left(\frac{m\pi}{L}x\right)\Big/ \cdot \sin\left(\frac{n\pi}{L}x\right),\ \int_0^L dx[/tex]
And the integral on the right would give me Kronecker delta which would 'kill' the sum so I would get the [tex]A_n[/tex] from that. But here I don't have this simple way. How should I get the [tex]A_m,\ B_m,\ C_m,\ D_m[/tex]?