Equilibrium Tension Along a Curved String

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The discussion revolves around determining the tension in a string supporting a pulley and block system. Participants emphasize the importance of analyzing the angles and components of tension at the pulley, noting that the horizontal components are equal. The solution involves geometric relationships to express the angles in terms of the string length and the distance between the walls. One contributor suggests projecting the string line to simplify the calculations. Ultimately, the original poster successfully finds the answer after clarifying their working process.
Raghav anand
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Homework Statement


A light inextensible string of length l hangs on two pegs attached to parallel walls separated by a height. A small frictionless pulley of weight Wp is attached to a block of weight Wb. When it is placed on the string, the string becomes taut and pulley runs on the string till equilibrium is established. What is the tension in the string?

Homework Equations


F=ma; vertically and horizontally
x, l, Wp, Wb are the given variables

The Attempt at a Solution


The angles the tension force makes with the pulley at the point of contact are equal as the horizontal components of tension are equal. When equating the vertical component to mg, I only get an expression for T in terms of an unknown variable h. I eliminated y by using the two triangles marked in the diagram. Any thoughts?
 
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What is the length between two walls?
 
Raghav anand said:
[
The angles the tension force makes with the pulley at the point of contact are equal as the horizontal components of tension are equal. When equating the vertical component to mg, I only get an expression for T in terms of an unknown variable h. I eliminated y by using the two triangles marked in the diagram. Any thoughts?
I gather the distance between the walls is x.
You should post more of your working, preferably typed, not as an image.
You should be able to find the angle in terms of l and x only - it's just geometry. Hint: project the line of one side of the string down until it reaches the opposite wall. After that it is straightforward.
 
I will make sure to write more from next time. Got the answer, thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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