Equipotential Surfaces physics problems

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The discussion focuses on solving a physics problem involving charge distribution on two concentric spheres. It utilizes charge conservation and the concept of equipotential surfaces, applying Gauss's law to determine the charges on the inner and outer spheres. The calculations suggest that when connected by a wire, the total charge of -5Q will redistribute to minimize potential energy while adhering to Gauss's law. The user expresses uncertainty about the concept of equipotential surfaces and seeks clarification on their understanding. Overall, the problem illustrates the principles of electrostatics and charge behavior in conductors.
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Homework Statement


attachment.php?attachmentid=60700&stc=1&d=1375709755.png

Homework Equations


- Charge conservation
- Equipotential surfaces

The Attempt at a Solution


Let Q1 be the amount of charge on the inner sphere with radius c, and Q2 be the amount of charge on the outer sphere with radius b.
Using Gauss's law, I figured out that Q1=+2Q and Q2=-2Q
1/ Charge conservation: Q1+Q2=0 (1)
2/ Equipotential surfaces: \frac{kQ_{1}}{c}=\frac{kQ_{2}}{b}(2)
(1),(2)=>Q1=Q2=0
Since my understanding on equipotential surfaces is not very good, please correct me if I am wrong, thank you!
 

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Do you even need calculation? When they are joined by a wire the two spheres can be said to be parts of the same conductor. We know that the total charge on the conductor is -5Q. There are many ways to distribute this charge but they will move so as to minimise the potential energy of the system and obey Gauss law. What will happen? (This situation is same as that of a solid spherical conductor with a cavity).
 
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