- #36
Sat-P
- 53
- 4
Can someone just solve this question and tell me the answer?
Yes, essentially.Sat-P said:Are you asking about the magnitude of the current leaving node 0 which flowed through resistor 2-0?
Yes! Do you see how that follows from symmetry?Sat-P said:Is current flowing through resistor 0-2 the same as the current flowing through resistor 0-5
Oh my!haruspex said:Yes! Do you see how that follows from symmetry?
And what about the remaining radial pair, 3-0 and 0-4?
Perhaps you should review the Homework forum guidelines.Sat-P said:Can someone just solve this question and tell me the answer?
A good idea ! (the naming in #1 is rather confusing)haruspex said:Can you be clearer? Number the nodes 1 to 6 anticlockwise around the hexagon starting with 1 at a. Call the centre 0.
It must be, by symmetry.Sat-P said:I thought that current through resistor a0 and 0b will be the same
Please show the details.Sat-P said:when I interpreted this mathematically I got that the current through the resistor 0b will be less than that through the resistor a0
The image is too blurry to read with any confidence, but it looks to me that you are assuming the currents along the three resistors connected to a are equal. That's not how electricity works.Sat-P said:I am sorry for the misinterpretation, but the current through resistor 0b will be more i.e 0.65 i (approx) and current through resistor a0 is 0.334 I (approx). You can see the results in the image above. I've edited the above post.
Can you please clarify why the current through the resistors connected to a should not be equal?haruspex said:The image is too blurry to read with any confidence, but it looks to me that you are assuming the currents along the three resistors connected to a are equal. That's not how electricity works.
See my edit to my previous post.Sat-P said:Can you please clarify why the current through the resistors connected to a should not be equal?
How can you say that the current through ab is 2 Ampereharuspex said:See my edit to my previous post.
It's the law (Ohm's law, to be specific).Sat-P said:How can you say that the current through ab is 2 Ampere
Got itBvU said:It's the law (Ohm's law, to be specific).
##\ ##
So can you solve it now using the splitting up of node 0?Sat-P said:Got it
In post #32 you recognised (guessed?) that, by symmetry, the current along 2-0 is the same as along 0-5. That allows you to split ##0_{2345}## into two nodes, ##0_{25}, 0_{34}##.Sat-P said:Even after I split the node 0ab , the other radial resistors are causing me trouble, if I can get a way to simplify them then it will be all good
Agrees with mine, but I didn't double check.Sat-P said:After solving this one I got 11R/20 so is it the answer, did I do it right
The answer isn't really the important element. Whther you did it right can only be confirmed if you post your work.Sat-P said:After solving this one I got 11R/20 so is it the answer, did I do it right