- #1
Kasper_NYC
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What kind of thermodynamic process is the compression of a gas when the volume varies reducing it, and the temperature increase, and there is an exchange of temperature with the exterior (the walls of the compressor are refrigerated, but I assume that the gas will increase its temperature a little bite because the compression).
I am trying to find the formula in order to calculate the needed Work to compress 1Kg of CO2 (molecular weight 44.01g/mol), at 278.15K, from 0.067 liters at 30 atm of pressure, to 0.057 liters at 35 atm.
I though the thermodynamic process could be something close to an isothermal process, because the compressor is refrigerated, trying to keep the inicial temperature, and the estimation that I got for an isothermal process is:
From the formula W = n * R * T * Ln (Vb / Va)
W = Watios
n (number of moles) = 22.72
R (Constant) = 0.082
T (Kelvin degrees) = 278.15 K
Vb = 0.067 liters
Va = 0.057 liters
W = 22.72 * 0.082 * 278.15 * Ln (0.067/0.057)
W = 22.72 * 0.082 * 278.15 * 0.16 = 82.91W
Please, is it this estimation right? What it could be the right Thermodynamic process?
Best and thanks.
PS - I apologize for my English, I am learning it.
I am trying to find the formula in order to calculate the needed Work to compress 1Kg of CO2 (molecular weight 44.01g/mol), at 278.15K, from 0.067 liters at 30 atm of pressure, to 0.057 liters at 35 atm.
I though the thermodynamic process could be something close to an isothermal process, because the compressor is refrigerated, trying to keep the inicial temperature, and the estimation that I got for an isothermal process is:
From the formula W = n * R * T * Ln (Vb / Va)
W = Watios
n (number of moles) = 22.72
R (Constant) = 0.082
T (Kelvin degrees) = 278.15 K
Vb = 0.067 liters
Va = 0.057 liters
W = 22.72 * 0.082 * 278.15 * Ln (0.067/0.057)
W = 22.72 * 0.082 * 278.15 * 0.16 = 82.91W
Please, is it this estimation right? What it could be the right Thermodynamic process?
Best and thanks.
PS - I apologize for my English, I am learning it.