- #1
paweld
- 255
- 0
How to evaluate the following integral using residue theorem:
[tex]
\int_1^2 (x+1) \sqrt[6]{\frac{x-1}{2-x}}dx
[/tex]
(The answer is [tex]\frac{31}{36}\pi [/tex])
Thanks for any help
[tex]
\int_1^2 (x+1) \sqrt[6]{\frac{x-1}{2-x}}dx
[/tex]
(The answer is [tex]\frac{31}{36}\pi [/tex])
Thanks for any help