Evaluate Summation of 1/e^n from 0 to Infinity

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In summary, the formula for evaluating the summation of 1/e^n from 0 to infinity is Σ (1/e^n) = 1 + 1/e + 1/e^2 + 1/e^3 + ... + 1/e^n, where n represents the number of terms in the summation. To calculate the sum, you can use the formula Σ (1/e^n) = a / (1 - r), where a is the first term (1) and r is the common ratio (1/e). The significance of this summation lies in its representation of a finite geometric series with a common ratio less than 1. The sum can be approximated by taking a finite number of terms,
  • #1
annoymage
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Homework Statement



evaluate
[tex]\sum[/tex][tex]\frac{1}{e^n}[/tex] from 0 -> infinity

Homework Equations



N/A

The Attempt at a Solution



from what I've learn, i can calculate summation i in form

[tex]\sum[/tex]na ,a is integer
or
[tex]\sum[/tex] f(n+1)-f(n)

but how to make 1/e^n in any those form?
can give me any clue please

Homework Statement


Homework Equations


The Attempt at a Solution

 
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  • #2
Hint: Think about geometric series
 
  • #3
LCKurtz said:
Hint: Think about geometric series

[tex]\sum[/tex]([tex]\frac{1}{e}[/tex])n

yes, why am i so stupid didn't think of that =.=

thank you very much
 

FAQ: Evaluate Summation of 1/e^n from 0 to Infinity

What is the formula for evaluating the summation of 1/e^n from 0 to infinity?

The formula for this summation is Σ (1/e^n) = 1 + 1/e + 1/e^2 + 1/e^3 + ... + 1/e^n, where n represents the number of terms in the summation.

How do you calculate the sum of 1/e^n from 0 to infinity?

To calculate the sum of this infinite series, you can use the formula Σ (1/e^n) = a / (1 - r), where a is the first term (1) and r is the common ratio (1/e). This results in the sum being equal to 1 / (1 - 1/e) = e / (e - 1).

What is the significance of evaluating the sum of 1/e^n from 0 to infinity?

This summation is significant because it represents the sum of a geometric series with a common ratio less than 1. This means that the sum is finite, and it converges to a specific value as the number of terms increases towards infinity. It is also used in various mathematical and scientific calculations and models.

Can the summation of 1/e^n from 0 to infinity be approximated?

Yes, the sum can be approximated by taking a finite number of terms in the series. As the number of terms increases, the approximation becomes closer to the actual value of the summation. This is often used in numerical calculations where the infinite series cannot be evaluated directly.

What is the value of the summation of 1/e^n from 0 to infinity?

The value of this sum is approximately 1.582. However, it is an irrational number and cannot be expressed as a fraction or a finite decimal. It is often represented by using the constant e, which is approximately equal to 2.71828.

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