Evaluate the definite integral

In summary: You don't necessarily need to change the limits of integration. If, after you have your antiderivative (as a function of u), you can undo the substitution to get the equivalent form in terms of x. At that point just plug in the limits of integration.
  • #1
purdue2016
2
0

Homework Statement


Evaluate the definite integral from 0 to 18.
∫[x/(9+4x)^1/2]dx

Homework Equations





The Attempt at a Solution


I know to use u-substitution and I set u = (9+4x)^1/2. I can't figure out where I'm messing up because I keep ending up with very large numbers which are incorrect.
 
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  • #2
My first move would be to simplify the surd with x = 9u/4. Seeing the (1+u)-1/2 that results, I would then use a trig substitution for u. tan2 or sinh2 will eliminate the surd.
 
  • #3
purdue2016 said:

Homework Statement


Evaluate the definite integral from 0 to 18.
∫[x/(9+4x)^1/2]dx

Homework Equations





The Attempt at a Solution


I know to use u-substitution and I set u = (9+4x)^1/2. I can't figure out where I'm messing up because I keep ending up with very large numbers which are incorrect.
Your substitution should work. Show us what you did.

When you make your substitution, make sure that you change everything. You shouldn't have x's and dx's in your integral after the substitution.
 
  • #4
I finally got it using the substitution I mentioned. I think I was screwing up because I didn't change the limits of integration for the new variable. Thanks for the help.
 
  • #5
haruspex said:
My first move would be to simplify the surd with x = 9u/4. Seeing the (1+u)-1/2 that results, I would then use a trig substitution for u. tan2 or sinh2 will eliminate the surd.
If the radicand were the sum or difference of squares, I would take this approach, but in this case a much simpler approach will work.
 
  • #6
purdue2016 said:
I finally got it using the substitution I mentioned. I think I was screwing up because I didn't change the limits of integration for the new variable. Thanks for the help.

You don't necessarily need to change the limits of integration. If, after you have your antiderivative (as a function of u), you can undo the substitution to get the equivalent form in terms of x. At that point just plug in the limits of integration.

Schematically it's like this:
$$ \int_a^b f(x) dx = \int_{x = a}^b g(u)du = G(u)\vert_{x = a}^b = F(x)\vert_{x = a}^b = F(b) - F(a)$$

If you decide not to change the limits of integration, it's helpful to note that they are values of x by adding "x = ..." in the lower limit.
 
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FAQ: Evaluate the definite integral

What is the purpose of evaluating a definite integral?

The purpose of evaluating a definite integral is to find the numerical value of the area under a curve between two given points on the x-axis. This can be useful in various applications such as calculating displacement, velocity, and acceleration in physics, or finding the total amount of a substance in a chemical reaction.

How do you evaluate a definite integral?

To evaluate a definite integral, you first need to find the indefinite integral of the given function. Then, plug in the upper and lower limits of integration into the indefinite integral and subtract the resulting values to find the numerical value of the definite integral.

What are the limits of integration in a definite integral?

The limits of integration in a definite integral are the upper and lower bounds that determine the range of x-values over which the area is being calculated. These limits are typically denoted as a and b in the integral notation, ∫abf(x) dx.

Can you evaluate a definite integral using the Fundamental Theorem of Calculus?

Yes, the Fundamental Theorem of Calculus states that the definite integral of a function can be evaluated by finding the antiderivative of the function and plugging in the upper and lower limits of integration. This is also known as the First Fundamental Theorem of Calculus.

Are there any other methods for evaluating a definite integral?

Yes, there are other methods for evaluating a definite integral such as the substitution method, integration by parts, and trigonometric substitution. These methods can be useful for more complex integrals that cannot be evaluated using the basic rules of integration.

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