Evaluating ln(x + sqrt[1+x2]) - sin(x) at x=.001

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To evaluate the function ln(x + sqrt[1+x^2]) - sin(x) at x = 0.001, the power series expansions for sin(x) and ln(1 + x) are essential. For small values of x, sin(x) can be approximated as x, simplifying the calculation. The ln function also requires modification of its series expansion to fit the expression. Substituting these approximations allows for a more straightforward evaluation of the function at the specified point. This approach effectively simplifies the problem, making it easier to find the solution.
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Homework Statement


The problem I'm attempting to solve asks you to evaluate the function at a given point. In this case:

ln(x + sqrt[1+x2] ) - sin(x)
@ x = .001


Homework Equations


sin(x) = x - (x3/3!) + (x5/5!) - (x7/7!) + ...
AND
ln(1 + x) = x - (x2/2) + (x3/3) - (x4/4) + ...


The Attempt at a Solution


I know I'm supposed to substitute in the power series expansions, but I'm not sure how to begin modifying the second expansion to suit my needs in solving the problem. Can anyone point me in the right direction?
 
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Since x is small, you can approximate sin(x) as just x, you can do the same with the other functions.
 

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