Exactly why FTLC is impossible with entangled photons?

In summary, it is written that almost all physics books and courses state that entangled photons cannot be used for faster than light communication. The question of used entangled photons to communicate faster than light has been discussed before, but I was not able to understand why it is impossible. My goal is not to prove that many physicists and scientists are wrong about this, but to provide some superficial knowledge on quantum physics. According to my understanding, the probability for a photon to pass through a filter depends on the angle Φ between the photon and the filter polarization axis. Imagine some photons that are entangled and sent far away with Jack and Joe. They have agreed beforehand that they’ll send message to each other every 24 hours (or every 12 pm).
  • #36
Nugatory said:
Now suppose that Alice changes her angle to something else, which we'll call ##\theta##. The stream of photons reaching Bob is made up 50% of photons polarized along the angle ##\theta## and 50% polarized along the angle ##\theta+\pi/2##.

So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?
 
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  • #37
Mentz114 said:
I don't understand why you two are arguing when you both must believe that a separable conditional probability ##P(xy|\alpha\beta)=P(x|\alpha)P(y|\beta)## cannot reproduce the predictions of QT ?

Beats me as well. All I am saying is the rules of normal probability theory are not respected in QM which is hardly surprising since it is a different probability model. If you want it to be like ordinary probability theory you need non-locality. But for some reason he thinks Bell has nothing to do with probability.

Thanks
Bill
 
  • #38
Karagoz said:
So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?
If a photon does not pass a filter it is gone. All the photons that pass a polarizer are aligned to the polarizer angle.
 
  • #39
Karagoz said:
So when Alice changes her angle to Φ, and passes his photons through that filter, 50% pass through it and 50% don't. So The stream of photons reaching Bob is made up 50% of photons polarized along the angle Φ and 50% polarized along the angle Φ+1/2π.

Shouldn't it be that P=cos^2(Φ) of Alice's photons pass through his filter when he changes her angle to Φ?
The ones that arrive at Bob with polarization ##\phi+\pi/2## also encounter Bob's filter and contribute to the number passing through it. What is ##\cos^2(\phi+\pi/2)##?
 
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Likes Karagoz and bhobba
  • #40
Nugatory said:
The ones that arrive at Bob with polarization ##\phi+\pi/2## also encounter Bob's filter and contribute to the number passing through it. What is ##\cos^2(\phi+\pi/2)##?

We are talking aboit a new set of entangled photons when Alice changes his polarization filter. So almost same thing happens again.

Thanks, I think I got it if I'm not wrong.
 
  • #41
The question has been answered so its time to close it.

Thanks
Bill
 

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