Example of h: R->R^2 such that h is onto

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In summary, the conversation is discussing the challenge of finding an example of a function h: R --> R^2 that is onto. The participants suggest using a bijection or a continuous surjection, such as the Peano space filling curve. They also discuss the difficulty in finding a function using the t--> (f(t),g(t)) approach and suggest using decimal notation instead.
  • #1
kkitkat
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example of h: R-->R^2 such that h is onto

Hello everyone,

can anyone suggest an example of a function h: R --> R^2 such that h is onto. All I could come up with is the following:

h: R --> R^2 ==>

f(x) = y1
g(x) = y2

==> for h to be onto I need to find a function that gives me the following:

f^(-1)(y1) = g^(-1)(y2),

where f^(-1) is the inverse of f and g^(-1) is the inverse of g,

but I can't think of any. Can anyone please give me a hint in the right direction.

Thanks a lot
 
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  • #2
What relation do f and/or g have to do with h?

It is trivial to find examples like this, as long as you 'do it by force'. The two sets clearly have the same cardinality, so they are in bijection.

Or do you actually want a continuous surjection? Try the Peano space filling curve.
 
  • #3
matt grime said:
What relation do f and/or g have to do with h?

It is trivial to find examples like this, as long as you 'do it by force'. The two sets clearly have the same cardinality, so they are in bijection.

Or do you actually want a continuous surjection? Try the Peano space filling curve.

Well, as far as I understand R-->R^2 functions it goes like this: h(t)=(3t, t) so in this example f(t) is 3t and g(t) is t. But obviously h(t) is not onto. And I'm sure that the solution is trivial, but for some reason I just can't see it. I'm not a mathematician so most of the things you've mentioned are away over my head :( If anyone could dumb it down for me a bit, I would really appreciate it
 
  • #4
You're thinking of far too nice functions. Functions typically don't look like t-->3t.

How about this one: take a real number, write it in decimal notation, then do something with the digits?

You are never going to get a function by thinking about t-->(f(t),g(t)). For a start, fix an x and consider {t: f(t)=x}. That will have to be an uncountable set: h has to map to every pair (x,y), and there are uncountably many y to hit for each x.
 

FAQ: Example of h: R->R^2 such that h is onto

What does "h is onto" mean in this context?

In this context, "h is onto" means that for every element in the range of h (R^2), there exists at least one element in the domain of h (R) that maps to it. In other words, h covers or "hits" every point in the range.

Can you provide an example of a function h: R->R^2 that is onto?

One example of a function h: R->R^2 that is onto is h(x) = (x, x^2). This function maps each real number x to a point on the parabola y = x^2 in the Cartesian plane.

How can you determine if a given function h: R->R^2 is onto?

To determine if a function h: R->R^2 is onto, you can check if every element in the range of h (R^2) has at least one corresponding element in the domain of h (R) that maps to it. Another way is to check if the range of h (R^2) is equal to the codomain of h (R^2).

What is the importance of a function being onto?

A function being onto is important because it means that every element in the range is being "hit" or mapped to by at least one element in the domain. This ensures that there are no "gaps" or missing elements in the range and that the function is able to cover all possible outputs.

Is it possible for a function h: R->R^2 to be both onto and one-to-one?

Yes, it is possible for a function h: R->R^2 to be both onto and one-to-one. This type of function is called a bijection and it means that every element in the range of h (R^2) has exactly one corresponding element in the domain of h (R) that maps to it.

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