- #1
Thijs982
< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >
Hey,
For our project we have to think of an experiment that can kind of simulate a rocket. We decided to use a fire extinguisher on a kart, since its mass constantly changes (same with a rocket). To calculate the thrust force that the extinguisher provides we need the u ( exhaust velocity) and mdot (the mass flow rate).
The NASA site gives us two ways to calculate mdot (https://www.grc.nasa.gov/WWW/k-12/VirtualAero/BottleRocket/airplane/mflchk.html) But for both ways an exhaust velocity is needed.
On a kerbal forum (https://forum.kerbalspaceprogram.com/index.php?/topic/38334-how-much-dv-is-in-fire-extinguisher/) two guys calculate the exhaust velocity via two ways. One with the internal energy and the other one using Thrust. I am currently trying it with internal energy but i am kind of stuck.
I know that it is an adiabatic proces thus the change in U (internal energy) is equal to -3/2 * n * R * dT, but I don't know how much of the internal energy gets transformed in kinetic energy to propel the gas.
Can somebody please explain to me, or help me calculate mdot and the exhaust velocity of my fire extinguisher
Kind Regards,
Thijs
Specs of the extinguisher:
5kg of CO2 fuel
Pressurized to 70 bar
weight 12.3 kg excluding fuel
Dimension = 670 mm x 170 mm
<Moderator's note: advertisement removed>
Hey,
For our project we have to think of an experiment that can kind of simulate a rocket. We decided to use a fire extinguisher on a kart, since its mass constantly changes (same with a rocket). To calculate the thrust force that the extinguisher provides we need the u ( exhaust velocity) and mdot (the mass flow rate).
The NASA site gives us two ways to calculate mdot (https://www.grc.nasa.gov/WWW/k-12/VirtualAero/BottleRocket/airplane/mflchk.html) But for both ways an exhaust velocity is needed.
On a kerbal forum (https://forum.kerbalspaceprogram.com/index.php?/topic/38334-how-much-dv-is-in-fire-extinguisher/) two guys calculate the exhaust velocity via two ways. One with the internal energy and the other one using Thrust. I am currently trying it with internal energy but i am kind of stuck.
I know that it is an adiabatic proces thus the change in U (internal energy) is equal to -3/2 * n * R * dT, but I don't know how much of the internal energy gets transformed in kinetic energy to propel the gas.
Can somebody please explain to me, or help me calculate mdot and the exhaust velocity of my fire extinguisher
Kind Regards,
Thijs
Specs of the extinguisher:
5kg of CO2 fuel
Pressurized to 70 bar
weight 12.3 kg excluding fuel
Dimension = 670 mm x 170 mm
<Moderator's note: advertisement removed>
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