Expansion difficulty with clearance

In summary, an 80mm aluminum alloy piston fits into a cast iron cylinder with a radial clearance of 0.75mm at 15C temp. The piston and cylinder reach 120C.
  • #1
german1234
9
0

Homework Statement



An 80mm aluminium alloy piston fits into a cast iron cylinder with a uniform radial clearance of 0.75mm at 15C temp.the piston and cylinder reach 120C.

1. Determine radial clearance at 120C
2.what is diametral clearance 120C
3.What is change in cross sectional area of piston.

I am given coefficients of linear expansion for both metals.
aluminium alloy: 19x10^-6/C
iron: 10x10^-6/C



Homework Equations



I know how to use the formula for linear expansion and area expansion.

The Attempt at a Solution




Part 1 is what gives me trouble.
I am not sure what radial clearance means.I think it means the gap between the piston and the iron cylinder.
In that case, I can use the formula to find how much the piston expands.
I need to find the expansion of the piston and the expansion of the metal cylinder and take these two answers away from 0.75mm to find the new radial clearance.

My problem is: How do I find the expansion of the iron cylinder?


Part 2:
If I have found the radial clearance, then I can multiply it by 2 and that will give me the diametral clearance?

Part 3:
Change in cross-sectional area:

jjust fill in the formula for this using original cross-sectional area to find new area
 
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  • #2
german1234 said:
My problem is: How do I find the expansion of the iron cylinder?
If you know how to find the expansion of the aluminum piston, you use the same method (Except that you use the thermal expansion coefficient of iron, not aluminum.)
Don't know if that is what you are asking, post back if you meant to ask something else.
 
  • #3
thanks,
I don't know what the original thickness of the iron is, so i can't figure out by how much it expands
 
  • #4
Is the 0.75mm the figure i need to use for the iron?
 
  • #5
The iron has a radius that is 0.75 mm larger than that of the aluminum.
 

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