- #1
JD_PM
- 1,131
- 158
Let us set up a very simple circuit, with two resistors in series as shown in the sketch.
We know that for this particular circuit ##V_{14} = V_{12} + V_{23}##. But what I have always wondered is:
How does the circuit "know" that once I introduce a battery of ##8 V## that each of the bulbs will yield ##4V##?
I remember asking a similar question back in my bachelor years (general physics III course) and getting an answer like "due to Kirchhoff's voltage law: The sum of the potential differences around any closed loop is zero" but, in my opinion, this does not answer the question. Kirchhoff's law explains the experimental result but my question is more about how does the circuit manage to split the ##8V## of the battery into ##4V## volts for each bulb.
We all agree that switching on the battery and the split does not happen simultaneously.
My question, in other words, is: how can the split be explained?
Thank you!
We know that for this particular circuit ##V_{14} = V_{12} + V_{23}##. But what I have always wondered is:
How does the circuit "know" that once I introduce a battery of ##8 V## that each of the bulbs will yield ##4V##?
I remember asking a similar question back in my bachelor years (general physics III course) and getting an answer like "due to Kirchhoff's voltage law: The sum of the potential differences around any closed loop is zero" but, in my opinion, this does not answer the question. Kirchhoff's law explains the experimental result but my question is more about how does the circuit manage to split the ##8V## of the battery into ##4V## volts for each bulb.
We all agree that switching on the battery and the split does not happen simultaneously.
My question, in other words, is: how can the split be explained?
Thank you!