Explanation for bright fringes in Single Slit Diffraction

  • #1
Aurelius120
251
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TL;DR Summary
The formula for position of bright fringes of Single Slit Fraunhoffer diffraction is given by $$a\sin(\theta_n)=\frac{(2n+1)\lambda}{2}$$
$$\theta_n \approx \sin(\theta_n) \approx \tan(\theta_n)=\frac{x_n}{D}$$
##n=1,2,3,......##
Looking for an intuitive explanation for this formula.
The central bright fringe is brightest. Why?
In Young's Double Slit Experiment, we were shown the complete derivation for location of fringes, width of fringes etc. on interference by two point sources of light and all was well.
In Single Slit Diffraction we were just asked to remember the formulae as they were with little explanation.

I understand that all waves from points equidistant from slit-center on either side interfere constructively at the screen-center but why don't they cancel with waves from points that are in opposite phase? Why are waves from every point interfering constructively with waves from every other point? If there is a combination of both constructive and destructive, why is it brighter than other bright fringes?

A little research gives a clear explanation for dark fringes and why they are formed at path difference of ##n\lambda##. For example here.

However I cannot find an explanation for formation of maxima at ##\Delta x=\frac{(2n+1)\lambda}{2}##? Is the explanation intuitive or is the reason purely mathematical?(perhaps too complicated to be taught)
 
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  • #3
BvU said:
Although there is a progressive change in phase as you choose element pairs closer to the centerline, this center position is nevertheless the most favorable location for constructive interference of light from the entire slit and has the highest light intensity if the Fraunhofer diffraction expression is reasonably applicable. If the conditions D >> a and D>> a2/λ are not met for this combination of slit width and screen distance, the Fresnel diffraction result may not have maximum intensity on the centerline.

Still don't understand why it is brightest?
1000016216.jpg

A and B will interfere constructively with each other but destroy C and then other points on either side will destroy whats left. It will be a Central Dark Fringe , Right?

And still don't see why bright fringe at odd multiples of half wavelength
 
  • #4
I'm looking at the bottom half of lecture notes (Prof. Dmitri Pogosian, Alberta Ca), based on Young and Freedman, 12th ed. (I only have 11th ed, pp 1369...1376) and really don't know what to add.

And there's always the hyperphysics explanation (4 pages, phasors, etc)

Aurelius120 said:
In Young's Double Slit Experiment, we were shown the complete derivation for location of fringes, width of fringes etc. on interference by two point sources of light and all was well.
Note that there too the single-slit pattern appears -- as an envelope

##\ ##
 
  • #5

FAQ: Explanation for bright fringes in Single Slit Diffraction

What causes the bright fringes in single slit diffraction?

The bright fringes in single slit diffraction are caused by constructive interference of light waves that pass through the slit. When light waves emanate from different parts of the slit, they spread out and overlap. At certain angles, the path difference between waves from different parts of the slit results in constructive interference, leading to bright fringes on a screen.

How does the width of the slit affect the pattern of bright fringes?

The width of the slit significantly affects the diffraction pattern. A narrower slit results in wider spacing between the bright fringes, while a wider slit produces a more closely spaced pattern. This is because a narrower slit causes greater spreading of the light waves, leading to more pronounced diffraction effects.

Why do the bright fringes decrease in intensity as you move away from the center?

The intensity of the bright fringes decreases as you move away from the center due to the distribution of light intensity and the effects of diffraction. As the angle increases, the path differences between waves from different parts of the slit become more significant, leading to increased destructive interference, which reduces the overall intensity of the fringes.

What is the mathematical relationship that describes the positions of the bright fringes?

The positions of the bright fringes in single slit diffraction can be described by the formula: a sin(θ) = mλ, where 'a' is the width of the slit, 'θ' is the angle of the fringe from the central maximum, 'm' is the order of the fringe (an integer), and 'λ' is the wavelength of the light used. The bright fringes occur at angles where this equation holds true for integer values of 'm'.

Can the phenomenon of single slit diffraction be observed with any type of light?

Yes, single slit diffraction can be observed with any type of coherent light source, including lasers and monochromatic light. However, the effects are most pronounced with light sources that have a wavelength comparable to the width of the slit. For example, using visible light with a slit width on the order of micrometers will yield clear diffraction patterns.

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