Exploding Object Problem: Solving for the Speed of the Third Fragment

  • Thread starter shadowice
  • Start date
In summary, a 48.0-kg body moving in the positive x-axis direction with a speed of 389 m/s breaks into three pieces after an internal explosion. One piece with a mass of 9.5 kg moves with a speed of 385 m/s in the positive y-axis direction, while a second piece with a mass of 3.0 kg moves with a speed of 413 m/s in the negative x-axis direction. Using the conservation of momentum, the speed of the third fragment (with a mass of 35.5 kg) can be calculated to be 551.33 m/s.
  • #1
shadowice
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Homework Statement


A 48.0-kg body is moving in the direction of the positive x-axis with a speed of 389 m/s when, owing to an internal explosion, it breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 385 m/s along the positive y axis. A second fragment, whose mass is 3.0 kg, moves away from the point of explosion with a speed of 413 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.

M= 48kg
M1 = 9.5kg
M2= 3 kg
M3= 35.5 kg
Fnet = 0


Homework Equations


p=mv
m1v1+m2v2+m3v3=mv0


The Attempt at a Solution




been trying to do p = 48*389 = 18672
then 3*-413 +35.5 * Vx = 18672
then get vx of 560.87
then do vy = 9.5*385 + 35.5 vy = -103.02
then vx^2+ vy^2 = v3^2 and i get 551.33 and its not accepting
 
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  • #2
shadowice said:

Homework Statement


A 48.0-kg body is moving in the direction of the positive x-axis with a speed of 389 m/s when, owing to an internal explosion, it breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 385 m/s along the positive y axis. A second fragment, whose mass is 3.0 kg, moves away from the point of explosion with a speed of 413 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.

M= 48kg
M1 = 9.5kg
M2= 3 kg
M3= 35.5 kg
Fnet = 0


Homework Equations


p=mv
m1v1+m2v2+m3v3=mv0


The Attempt at a Solution




been trying to do p = 48*389 = 18672
then 3*-413 +35.5 * Vx = 18672
then get vx of 560.87
then do vy = 9.5*385 + 35.5 vy = -103.02
then vx^2+ vy^2 = v3^2 and i get 551.33 and its not accepting

Remember the following:

(1) Momentum before = Momentum After

(2) Momentum is a vector quantity so the momentum in the x direction must be conserved and separately momentum in the y direction must be conserved.

(3) Consequently the third piece moves in such a way as to guarantee number (2)
 
  • #3
figured out my error can delete this topic or close whichever you do
 

Related to Exploding Object Problem: Solving for the Speed of the Third Fragment

1. What causes an object to explode?

An object explodes when there is a rapid release of energy that causes it to burst apart. This can be due to a chemical reaction, build-up of pressure, or sudden release of stored energy.

2. Can any object explode?

Technically, any object has the potential to explode if the right conditions are met. However, some materials are more prone to explosions due to their chemical composition or physical properties.

3. How dangerous are exploding objects?

The danger of an exploding object depends on various factors such as the type of explosion, the size and location of the object, and the surrounding environment. Explosions can range from relatively harmless to extremely destructive and hazardous.

4. How can we prevent objects from exploding?

There are several ways to prevent objects from exploding, such as proper handling and storage, regular maintenance and inspection, and following safety protocols. Understanding the properties and potential hazards of different materials is also crucial in preventing explosions.

5. What should I do if I encounter an exploding object?

In case of an explosion, the first priority is to ensure your own safety and the safety of others. Follow evacuation procedures if necessary and call for emergency assistance. It is important to stay calm and follow any specific instructions provided by authorities.

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