Exploring Algebraic Sets: Finding Irreducibility and Prime Ideals

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In summary, the exercise involves showing that in $\mathbb{C}[X,Y,Z]$, the algebraic set $V(Y-X^2,Z-X^3)$ is equal to the set $\{(t,t^2,t^3)/ t \in \mathbb{C}\}$ and that the ideal of this set is generated by the polynomials $Y-X^2$ and $Z-X^3$. To prove this, we can use the fact that any solution of $Y-X^2=0$ and $Z-X^3=0$ in $\mathbb{C}[X,Y,Z]$ will also be a solution of $(t,t^2,t^3)$. This shows that $<Y
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evinda
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Hello! (Smile)

Notice that in $\mathbb{C}[X,Y,Z]$:
$$V(Y-X^2,Z-X^3)=\{ (t,t^2,t^3)/ t \in \mathbb{C}\}$$

In addition, show that:

$$I(V(Y-X^2,Z-X^3))=<Y-X^2,-X^3>$$

Finally, prove that the ideal $<Y-X^2,Z-X^3>$ is a prime ideal of $\mathbb{C}[X,Y,Z]$. Conclude that the algebraic set $V(Y-X^2,Z-X^3)$ is irreducible.

Could you give me some hints to solve the above exercise? (Thinking)
 
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Notice that in $\mathbb{C}[X,Y,Z]$:
$$V(Y-X^2,Z-X^3)=\{ (t,t^2,t^3)/ t \in \mathbb{C}\}$$

Could we do it maybe like that?

$$V(Y-X^2, Z-X^3)=\{(a,b,c) \in \mathbb{C}^3 | b-a^2=0, c-a^3=0 \Rightarrow b=a^2, c=a^3\}=\{(t, t^2, t^3)| t \in \mathbb{C}\}$$

In addition, show that:

$$I(V(Y-X^2,Z-X^3))=<Y-X^2,-X^3>$$

Is it like that?

$$I(V(Y-X^2, Z-X^3))=I(\{(t, t^2, t^3)|t \in \mathbb{C}\})=\{f(X,Y,Z) \in \mathbb{C}[X,Y,Z]|f(t,t^2,t^3)=0\}\overset{*}{=}\{(Y-X^2) \cdot g(X,Y,Z)+(Z-X^3) \cdot h(X,Y,Z) | g,h \in \mathbb{C}[X,Y,Z]\}=\langle Y-X^2, Z-X^3\rangle $$

At $(*)$ can we say it like that because we know from $V(Y-X^2, Z-X^3)=\{(t,t^2,t^3)|t \in \mathbb{C}\}$ that $(t,t^2,t^3)$ is a solution of $Y-X^2=0$ and $Z-X^3=0$ ?

(Thinking)
 

FAQ: Exploring Algebraic Sets: Finding Irreducibility and Prime Ideals

What is the purpose of exploring algebraic sets?

The purpose of exploring algebraic sets is to understand the structure and properties of mathematical equations and systems. By studying algebraic sets, we can gain insights into the behavior of polynomial equations and their solutions, and use this knowledge to solve problems in various fields such as physics, engineering, and computer science.

What are irreducible algebraic sets?

An irreducible algebraic set is a subset of a larger algebraic set that cannot be expressed as a union of two smaller algebraic sets. In other words, it is a set of points that cannot be divided into simpler components. Irreducible algebraic sets are important because they represent the fundamental building blocks of larger algebraic sets, and studying them can help us understand the structure of more complex sets.

How do we determine if an algebraic set is irreducible?

There are several methods for determining if an algebraic set is irreducible. One approach is to use the Nullstellensatz theorem, which states that an algebraic set is irreducible if and only if its corresponding ideal is prime. Another method is to check if the algebraic set can be written as a finite intersection of irreducible algebraic sets. If it cannot, then it is irreducible.

What are prime ideals in algebraic sets?

A prime ideal in an algebraic set is an ideal that satisfies two properties: it is proper (meaning it does not contain the entire set), and it is prime (meaning if a product of two polynomials is in the ideal, then at least one of the polynomials is also in the ideal). Prime ideals are important in algebraic sets because they help us understand the structure of the set and its irreducible components.

How can we use prime ideals to find irreducible components of an algebraic set?

One way to find irreducible components of an algebraic set is to first find all the prime ideals that correspond to the set. Then, we can use these prime ideals to generate a decomposition of the set into irreducible components. This process is known as primary decomposition, and it allows us to break down a complex algebraic set into simpler, irreducible pieces that are easier to analyze and understand.

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