- #1
lokofer
- 106
- 0
In fact if PNT says that the series [tex] \sum_{p<x}1 \sim Li(x) [/tex]
My question is if we can't conjecture or prove that:
[tex] \sum_{p<x}p^{q} \sim Li(x^{q+1}) \sim \pi(x^{q+1}) [/tex] q>0
In asymptotic notation...
My question is if we can't conjecture or prove that:
[tex] \sum_{p<x}p^{q} \sim Li(x^{q+1}) \sim \pi(x^{q+1}) [/tex] q>0
In asymptotic notation...