Exploring Bijective Holomorphic Maps on Open Sets and the Unit Circle

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In summary, the problem involves finding a relation between two bijective holomorphic maps f and g, given that they are both maps from an open set A to the unit circle and that a \in A, c=f(a), d=g(a). It is also mentioned that if the open set is connected and simply connected, the Riemann Mapping Theorem can be applied. Additionally, it is noted that f and g are biholomorphic and therefore conformal maps, which implies that they are angle preserving. The question asks if there is a way to relate the two conformal mappings to each other.
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semithinking
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Homework Statement


Let [tex]f[/tex] and [tex]g[/tex] be bijective holomorphic maps from an open set [tex]A[/tex] to the unit circle. Let [tex]a \in A[/tex] and [tex]c=f(a)[/tex] and [tex]d=g(a)[/tex]. Find a relation between [tex]f[/tex] and [tex]g[/tex] that involves [tex]a,c,d,f'(a),g'(a)[/tex].

Homework Equations


The Attempt at a Solution



If we also assumed that the open set is connected and simply connected, then we could apply the Riemann Mapping Theorem.
If that were the case, then there is a bijective holomorphic map [tex]f^{-1}: \text{unit circle} \rightarrow A [/tex] and [tex]g^{-1}: \text{unit circle} \rightarrow A [/tex] Then by the open mapping theorem, [tex]f: A \rightarrow \text{unit circle}[/tex] is continuous, thus a homeomorphism between [tex]A[/tex] and the unit circle.

I'm not sure where to start because we don't have that "connected and simply connected" assumption.
 
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We also know that [tex]f,g[/tex] are biholomophic which implies that it's a conformal map, thus it is angle preserving. Is this a way to two conformal mapping to each other?
 

FAQ: Exploring Bijective Holomorphic Maps on Open Sets and the Unit Circle

1. What is a bijective holomorphic mapping?

A bijective holomorphic mapping is a function that is both one-to-one (injective) and onto (surjective), and is also holomorphic, meaning it is complex differentiable at every point in its domain.

2. How is a bijective holomorphic mapping different from a regular holomorphic mapping?

A regular holomorphic mapping may not necessarily be bijective, meaning it may not have a unique inverse. However, a bijective holomorphic mapping guarantees a unique inverse, making it a bijection.

3. What are the properties of a bijective holomorphic mapping?

A bijective holomorphic mapping has the following properties: it is conformal (preserves angles), it preserves orientation, and it is topologically equivalent to a homeomorphism (continuous and invertible).

4. What are some examples of bijective holomorphic mappings?

Some examples of bijective holomorphic mappings include the exponential function, the logarithmic function, and the Möbius transformation.

5. What are the applications of bijective holomorphic mappings?

Bijective holomorphic mappings have many applications in complex analysis, including in the study of Riemann surfaces, conformal mapping, and complex differential equations. They are also used in other fields such as engineering, physics, and computer graphics.

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