- #1
alba
- 140
- 4
I have recently studied collisions, in which one or two bodies are already in motion.
I have tried to apply them to cases in which the bodies are initially at rest, like launching or kicking a ball etc, but they do not work.
Can you tell me how to google to find them, 'contact force' gives everything, I tried 'explosive forces' but I get only explosives.
Can you help me?:
suppose a girl (20 kg) on frictionless rollers launches a ball (1kg) doing work 210 J, what is the rule to find the outcome?
I imagine that if she pushes at a wall the outcome is the same of an elastic collision with a wall of a body of 20kg, , if so, she will move backward at v = √210*2/20 = - 4.58 m/s. Is that right?
Is the force on the wall equal to the force that acts on the girl? and what about momentum? the girl's is -91.6 kgm/s the wall's should be the same, but in that case it would mean it subtracted energy to the girl and her speed will be less?
How do I deal with the ball? do you have a link or a formula?
Thanks
I have tried to apply them to cases in which the bodies are initially at rest, like launching or kicking a ball etc, but they do not work.
Can you tell me how to google to find them, 'contact force' gives everything, I tried 'explosive forces' but I get only explosives.
Can you help me?:
suppose a girl (20 kg) on frictionless rollers launches a ball (1kg) doing work 210 J, what is the rule to find the outcome?
I imagine that if she pushes at a wall the outcome is the same of an elastic collision with a wall of a body of 20kg, , if so, she will move backward at v = √210*2/20 = - 4.58 m/s. Is that right?
Is the force on the wall equal to the force that acts on the girl? and what about momentum? the girl's is -91.6 kgm/s the wall's should be the same, but in that case it would mean it subtracted energy to the girl and her speed will be less?
How do I deal with the ball? do you have a link or a formula?
Thanks