- #1
Sebas4
- 13
- 2
- Homework Statement
- Boundary conditions electrostatics.
- Relevant Equations
- Meaning of the electric field variables in the boundary condition equations.
Hey, I have a really short question about electrostatics.
The boundary conditions are :
[tex] \mathbf{E}^{\perp }_{above} - \mathbf{E}^{\perp}_{below} = -\frac{\sigma}{\varepsilon_{0}}\mathbf{\hat{n}} [/tex],
[tex] \mathbf{E}^{\parallel }_{above} = \mathbf{E}^{\parallel}_{below}[/tex].
My question is what is [itex] \mathbf{E}^{\perp }_{above} [/itex], [itex] \mathbf{E}^{\perp }_{below} [/itex],
[itex] \mathbf{E}^{\parallel }_{above}[/itex] and [itex]\mathbf{E}^{\parallel}_{below}[/itex], is it the total electric field component near the boundary?
So is the electric field in this equation the sum of the external field and the electric field due to the charge at the boundary?
I will try to explain my question with an example.
Let's say we have an infinite plane with homogeneous charge density [itex]\sigma[/itex].
The electric field above the plane
[tex] \mathbf{E} = \frac{\sigma}{2\varepsilon_{0}}\mathbf{\hat{z}} [/tex].
The electric field below the plane is
[tex] \mathbf{E} = - \frac{\sigma}{2\varepsilon_{0}}\mathbf{\hat{z}} [/tex].
We have a homogeneous external field pointing in the z-direction, [itex]\mathbf{E}_{external} = \mathbf{E}_{0} \mathbf{\hat{z}}[/itex].
The electric field just below the surface of the plane is
[tex] \mathbf{E}_{total below} = \left(\mathbf{E}_{0} - \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} [/tex].
The electric field just above the surface of the plane is
[tex] \mathbf{E}_{total above} = \left(\mathbf{E}_{0} + \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} [/tex].
If we plug this in, in the boundary condition we get
[tex] \mathbf{E}_{total above} - \mathbf{E}_{total below} = \left(\mathbf{E}_{0} + \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} - \left(\mathbf{E}_{0} - \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} = \frac{\sigma}{\varepsilon_{0}} \mathbf{\hat{z}} [/tex].
This is true, according to the boundary condition.
I have also another question, this also works for non-homogeneous charge density boundaries? (I think so).
The boundary conditions are :
[tex] \mathbf{E}^{\perp }_{above} - \mathbf{E}^{\perp}_{below} = -\frac{\sigma}{\varepsilon_{0}}\mathbf{\hat{n}} [/tex],
[tex] \mathbf{E}^{\parallel }_{above} = \mathbf{E}^{\parallel}_{below}[/tex].
My question is what is [itex] \mathbf{E}^{\perp }_{above} [/itex], [itex] \mathbf{E}^{\perp }_{below} [/itex],
[itex] \mathbf{E}^{\parallel }_{above}[/itex] and [itex]\mathbf{E}^{\parallel}_{below}[/itex], is it the total electric field component near the boundary?
So is the electric field in this equation the sum of the external field and the electric field due to the charge at the boundary?
I will try to explain my question with an example.
Let's say we have an infinite plane with homogeneous charge density [itex]\sigma[/itex].
The electric field above the plane
[tex] \mathbf{E} = \frac{\sigma}{2\varepsilon_{0}}\mathbf{\hat{z}} [/tex].
The electric field below the plane is
[tex] \mathbf{E} = - \frac{\sigma}{2\varepsilon_{0}}\mathbf{\hat{z}} [/tex].
We have a homogeneous external field pointing in the z-direction, [itex]\mathbf{E}_{external} = \mathbf{E}_{0} \mathbf{\hat{z}}[/itex].
The electric field just below the surface of the plane is
[tex] \mathbf{E}_{total below} = \left(\mathbf{E}_{0} - \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} [/tex].
The electric field just above the surface of the plane is
[tex] \mathbf{E}_{total above} = \left(\mathbf{E}_{0} + \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} [/tex].
If we plug this in, in the boundary condition we get
[tex] \mathbf{E}_{total above} - \mathbf{E}_{total below} = \left(\mathbf{E}_{0} + \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} - \left(\mathbf{E}_{0} - \frac{\sigma}{2\varepsilon_{0}}\right) \mathbf{\hat{z}} = \frac{\sigma}{\varepsilon_{0}} \mathbf{\hat{z}} [/tex].
This is true, according to the boundary condition.
I have also another question, this also works for non-homogeneous charge density boundaries? (I think so).