Exploring Solutions for a System of Linear Equations with Variable Coefficients

In summary, the conversation discusses how to show that a system of linear equations either has a solution or has multiple solutions, specifically using the example of a system of three equations with three variables and parameter "a". The conversation also touches on the use of Gauss(-Jordan) elimination and the concept of dependent and inconsistent equations. The summary ends with a suggestion to use the determinant to determine the number of solutions for specific values of "a".
  • #1
lol_nl
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Homework Statement


How do I show that a system of linear equations either has a solution or has multiple solutions?

Homework Equations


Show that the system of equations
a*x _{1} + 2*x_{2} + a*x_{3} = 5a
x _{1} + 2*x_{2} + (2-a)*x_{3} = 5a
3*x _{1} + (a+2)*x_{2} + 6*x_{3} = 15

is solvable for every value of a. Solve the system for those values of a with more than one solution. Give a geometric interpretation of the system of equations and its solutions.

The Attempt at a Solution


I tried Gauss(-Jordan) elimination but because of the a's I could not get a nice solution.

How am I supposed to show that there is a solution regardless of what value of a I choose?

If there is more than one solution, at least one of the equations should be dependent on the other, so I should be able to reduce at least one row to all zeros? But there are multiple ways in which one or more of the equations can be a linear combination of the other two, right? E.g. I discovered that for a=1, eq. 1 and eq. 2 become equal. But how do I find all solutions?
 
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  • #2
I think you're just going to have to raise your threshold of pain and row-reduce the matrix.

I'll note, however, that there isn't a solution for every a. I find for two values of a, the system is inconsistent, so there is no solution.
 
  • #3
It's not too hard to show that there are three values of a for which the determinant of the matrix of coefficients is 0. Then put those specific values into determine whether there a none or an infinite number of solutions.
 

FAQ: Exploring Solutions for a System of Linear Equations with Variable Coefficients

What is a system of linear equations?

A system of linear equations is a set of two or more equations that involve the same variables and must be solved together. The solution to the system is the set of values for the variables that satisfies all of the equations in the system.

How do you solve a system of linear equations?

There are various methods for solving a system of linear equations, including substitution, elimination, and graphing. These methods involve manipulating the equations to isolate one variable, then using that value to solve for the other variables.

Can a system of linear equations have more than one solution?

Yes, a system of linear equations can have one unique solution, no solution, or infinitely many solutions. The number of solutions depends on the number of variables and the relationships between the equations in the system.

How do you know if a system of linear equations has no solution?

A system of linear equations has no solution if the equations are inconsistent, meaning they contradict each other and cannot be satisfied by any set of values for the variables. This can be determined by graphing the equations or by solving them and arriving at a logical impossibility, such as 2 = 3.

Can a system of linear equations have more equations than variables?

Yes, a system of linear equations can have more equations than variables. In this case, the system may be overdetermined, meaning there is no single solution that satisfies all of the equations. However, it is still possible for the system to have a unique solution or infinitely many solutions if the equations are not all independent.

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