Exploring the Acceleration of Two Falling Objects

In summary, the two objects in this problem, a block and a cylinder with unlimited string, have the same acceleration downwards. This can be shown by using the equations F=ma and torque, where the net force on each object is equal to the tension in the string minus the force of gravity. By setting these two equations equal to each other and simplifying, we can see that the masses of the two objects do not affect their acceleration, and thus they will fall at the same rate. Alternatively, conservation of energy can also be used to show that the accelerations are equal without finding their exact values.
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Homework Statement



One pulley, on one side we have a block with mass m.
On the other side we have a cylinder with mass m.
Cylinder (radius R) has unlimited string (massless, negligible thickness, no slippage)

So you can imagine two blocks falling as more string unravels from the cylinder.

I am told that these two objects have the same acceleration downwards. Why?

Homework Equations



F=ma
ma=mg-T

torque? T*R=I*[itex]\alpha[/itex]

The Attempt at a Solution



The problem made it sound like this was a quick, obvious argument.
I proceeded to a longer argument, finding that the accelerations of both masses were (2/3)g downward:

starting with the cylinder-
TR=I*[itex]\alpha[/itex]
T*R2 = (1/2)M*R2 * a
Finding T= (1/2)ma, then plugging T back into the standard F=ma equations.
Then I find the acceleration of the block to be (2/3)g as well.

Is this even right? If it is, was there a way to show that the objects' accelerations were the same without finding the actual accelerations?

The reason I don't think this is right is because I did the problem using conservation of energy using the assumption that the objects fell down at the same acceleration.
With conservation of energy I got acceleration=(1/2)g (conserving KE, PE, angular KE)
 
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  • #2


I think you don't need to use torque.
By F= m * a(center of mass) you get that their accel will only depend on forces applied to them. In both cases block and cylinder you have F = T - mg.
Then => m * aBlock = m * aCylinder => aBlock = aCylinder
 

FAQ: Exploring the Acceleration of Two Falling Objects

What is the acceleration of two falling objects?

The acceleration of two falling objects is the rate at which their velocity changes as they fall towards the ground. This acceleration is due to the force of gravity pulling the objects towards the Earth.

How is the acceleration of two falling objects affected by their masses?

The acceleration of two falling objects is not affected by their masses. According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Since both objects experience the same force of gravity, their masses do not affect their acceleration.

What factors can affect the acceleration of two falling objects?

The only factor that can affect the acceleration of two falling objects is the force of gravity, which is dependent on the mass and distance between the objects. Factors such as air resistance and surface area do not significantly impact the acceleration of falling objects in a vacuum.

Can the acceleration of two falling objects be different?

Yes, the acceleration of two falling objects can be different if they have different masses or are at different distances from the Earth's center of mass. However, in a vacuum, all objects will fall with the same acceleration due to the force of gravity.

Can the acceleration of two falling objects ever be zero?

Yes, the acceleration of two falling objects can be zero if there is no net force acting on them. This can occur if the objects are at rest or if they are falling at a constant velocity due to balanced forces. However, in a vacuum, the objects will eventually accelerate towards each other due to the force of gravity.

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