How Can Photons Have Momentum If They Have No Mass?

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Photons possess momentum despite having no rest mass, as explained through the Poynting vector, which relates electric and magnetic fields. In relativity, the momentum of a particle is defined differently, allowing for non-zero momentum even when mass approaches zero. The equation E^2 - (cp)^2 = (mc^2)^2 indicates that energy and momentum are still linked for massless particles like photons, where E = cp. The concept of relativistic mass helps clarify that a photon's momentum can be expressed as p = E/c. Thus, the relationship between energy and momentum confirms that photons can indeed have momentum without mass.
3dsmax
Wikipedia says that photons have momentum. How can that be possible since p=mv?
 
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3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?


The Poynting vector,S, gives momentum of light, and is given by:

S = E X B...E= electric field
B= magnetic field
X is cross product

However, this is the classical answer...and maybe this answer should be in classical section.:smile:
 
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3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?

According to relativity, the spatial momentum of a "particle" that has rest mass m is

p = \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}}.

To consider a photon, let m \rightarrow 0 and v \rightarrow c. This gives zero over zero, which is indeterminant, and can be anything (including non-zero values), depending on how the limits are taken.

Also, relaltivity says that for any particle,

E^2 - (cp)^2 = \left(mc^2\right)^2.

Even if m=0, p is non-zero when E is non-zero. In fact,

E = cp

for a photon.
 
i wish that i was in a higher physics class so that i could understand you.
 
3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?
The inertial mass M (aka relativistic mass) of a photon is defined just like the mass of all particles, as M/i] = p/v = p/c where p is the magnitude of the momentom and v is the particle's speed. I believe that you're thinking about a photon's proper mass m, which is zero for all photons.

The definition of the mass of a particle allows the following relation to be derived (let m = proper mass)

p = sqrt[1-(v/c)sup2]/c

This can be solved for m which in turn will be a function of the energy and momentum and when E = pc me will always turn out to be 0.

Pete
 
MOVING CLOCKS In this section, we show that clocks moving at high speeds run slowly. We construct a clock, called a light clock, using a stick of proper lenght ##L_0##, and two mirrors. The two mirrors face each other, and a pulse of light bounces back and forth betweem them. Each time the light pulse strikes one of the mirrors, say the lower mirror, the clock is said to tick. Between successive ticks the light pulse travels a distance ##2L_0## in the proper reference of frame of the clock...

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