- #1
Kinny
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Hi everybody]Since we see light, from the equation Δt=γ Δt' , Δt' (the Δtime in a photon) should be zero, cause γ→+∞ for v→c and Δt is a descrete number (if we actually see photons). So, I thought the time in a photon doesn't flow, but my Physic friend said it's wrong..? In the frequently asked question, it's written that the time "shrinks to zero", isn't that the same to say it doesn't flow in a photon?
Also, there's written that the distance shrinks to zero, but isn't suppose Δs'→+∞ ? Otherwise, for Δs=Δs' / γ , wouldn't we see the photons like "freeze", like not moving??
* γ = 1/ √(1-v^2 /c^2)
thanks for the answers...and sorry if I'm not approaching this in a very "elegant" way (i'm doing engineering XD
Also, there's written that the distance shrinks to zero, but isn't suppose Δs'→+∞ ? Otherwise, for Δs=Δs' / γ , wouldn't we see the photons like "freeze", like not moving??
* γ = 1/ √(1-v^2 /c^2)
thanks for the answers...and sorry if I'm not approaching this in a very "elegant" way (i'm doing engineering XD