Exploring the Dynamics of Forced Undamped Harmonic Oscillators

In summary, the Undamped Harmoni Oscillator differential equation has three solutions x(t), y(t) and H(s). The first solution is stable and the resonance solution has divergent Y(s). The second solution is stable and the transfer function is H(s)x(s). The third solution is stable and the oscillator stores energy from input. Plotting the total energy of the oscillator as a function of time will make more sense.
  • #1
Dcat
5
0
Undamped Harmoni Oscillator differential equation:
mx''=-kx
(solution (to IC: x(0)=A, x'(0)=0) : x=Acos(wt) with w2=k/m)

I need to find out the solution to the forced case with (Initial Condition zero):
mx''+kx=F (with F=AFcos(wFt) ) evaluating with the transfer function. But I m not sure this transfer function does exists, or is limied.

Second question) Is the solution to the Undamped HO forced sinusoidally stable ?
I suppose not, because without energy dissipation, the energy that enter is never consumed and just adds up to the system. But I m not sure, I have not time to calculate the solution which i haven't found.

Third ) In case of damped HO forced with a sinusoid, in the resonant band of frequencies, where there is amplification, the response function is higher than the input forcing sinusoid. Is a way to see the mathematic of energy transfer from input to output ? There is no creation of energy in the system , just the amplitude of the oscillation of the input is amplified, but this doesn't mean that the power of the output is higher than the input. Isn't it?
 
Physics news on Phys.org
  • #2
Not really. The transfer function here is not well-defined.

Working backwards from solution. (I'm not in the mood to derive all this. You can find it in any ODE text.)

[tex]x(t) = \frac{2 A_F}{m(\omega_F^2 - \omega_0^2)} sin(\frac{\omega_F + \omega}{2} t) sin(\frac{\omega_F - \omega_0}{2} t), \omega_F \neq \omega_0[/tex]

[tex]x(t) = \frac{A_F}{2 m} t sin(\omega_0 t), \omega_F = \omega_0[/tex]

(You might want to check the amplitudes, I scribbled them down rather hastily.)

You'll have to treat the two cases where omegas are different or same (resonance) separately. Let's take a look at the first case.

Input:
[tex]X(s) = L[A_F cos(\omega_F t)] = \frac{\delta(s - i \omega_F) + \delta(s + i \omega_F)}{2}[/tex]

Output:
[tex]Y(s) = L[x(t)] = \frac{A_F}{m(\omega_F^2 - \omega_0^2)} \frac{\delta(s + i \omega_0 + \delta(s - i \omega_0) - \delta(s + i \omega_F) - \delta(s - i\omega_F)}{2}[/tex]

And, of course, the transfer function H(s) must be such that Y(s) = H(s)X(s). This works everywhere except s= ±(iω0).

This solution is stable, of course, and the resonance solution has divergent Y(s), so obviously, there is no transfer function.

As far as power goes, the oscillator does no work, so there is no output power. The applied force does work on the oscillator if the phases match and against it if they don't. So the input power fluctuates between positive and negative if there is no resonance. In resonance, it's always positive, and energy stored in oscillator increases without bounds.
 
  • #3
Really thankyou for the math solution. This is exactly what I was looking for (and I already plotted some examples)! I need it for evaluating a system without damping factor, or without vibration absorber, just a metal frame joined with bolts very fixed. (I have a lot of cases and a lot of mathematic examples with the damping formula of SDOF model mx''+cx'+kx=F (where F=Afcos(wf*t)), but few formulas for the case of no damping c=0.)

There are still some question in my mind, without damping: in case wf is not the resonant freq w0, the response is clearly divergent; in the other case the solution is a sinusoid modulated with another sinusoid (or you can see it as a sinusoid (wf-w0) transmitted at higher freq (wf+w0) like in AM radio) (and I suppose the same energy of the input). Now consider the two case from a thermodynamic point of view, in the first case you are adding energy without dissipation, so energy adds up to the system and the oscillation becomes more and more large; but in the second case it looks like a periodic wave, which does not diverge, while I was expecting it to become more and more high. I am missing something, I know, but cannot figure it out.
 
  • #4
K^2 said:
As far as power goes, the oscillator does no work, so there is no output power. The applied force does work on the oscillator if the phases match and against it if they don't. So the input power fluctuates between positive and negative if there is no resonance. In resonance, it's always positive, and energy stored in oscillator increases without bounds.

So you mean in resonance the oscillator can store/absorbe energy, while not in resonance, the oscillator is somewhat transparent to the input vibration ?
 
  • #5
It stores energy from input either way. However, in non-resonance case, the input power isn't always positive. When the driving force pushes with oscillation, the work is positive. When it pushes against, it's negative. So your driving force isn't always supplying power to the oscillator. Half the time it is taking energy away from the oscillator.

Using the above solutions, try plotting the total energy of the oscillator as a function of time and comparing it to the plot of the oscillations themselves. Maybe it will make a little more sense.
 

FAQ: Exploring the Dynamics of Forced Undamped Harmonic Oscillators

What is the transfer function of an undamped harmonic oscillator?

The transfer function of an undamped harmonic oscillator is H(s) = 1/(ms^2 + k), where m is the mass of the oscillator and k is the spring constant. This transfer function describes the relationship between the input (force) and output (position) of the oscillator.

How does the undamped HO transfer function differ from the damped HO transfer function?

The undamped HO transfer function does not include a damping term, unlike the damped HO transfer function which includes a damping coefficient. This means that the undamped HO transfer function does not take into account any energy dissipation due to friction or resistance.

What is the significance of the mass and spring constant in the undamped HO transfer function?

The mass and spring constant determine the natural frequency of the oscillator, which is the frequency at which the oscillator will vibrate without any external force acting on it. The mass also affects the amplitude of the oscillator's motion, while the spring constant affects the stiffness of the spring and therefore the speed at which the oscillator returns to equilibrium.

Can the undamped HO transfer function be used to model real-world systems?

Yes, the undamped HO transfer function can be used to model systems that behave like an undamped harmonic oscillator, such as a mass-spring system. However, real-world systems often have damping present, so the damped HO transfer function may be a more accurate model in those cases.

How is the undamped HO transfer function derived?

The undamped HO transfer function is derived from the equation of motion for an undamped harmonic oscillator, which is given by mx'' + kx = 0. By taking the Laplace transform of this equation, we can solve for the transfer function H(s) = X(s)/F(s), where X(s) is the Laplace transform of the position x(t) and F(s) is the Laplace transform of the input force f(t).

Back
Top