- #1
Shackleford
- 1,656
- 2
Assuming a perfect sphere,
mg - w' = m (v^2/r)
g' = g - (v^2/r)
I understand there's a constant radial acceleration because we're not flying off the planet. Theoretically, the difference should be 0.0337 m/s^2, but isn't because the Earth "bulges" at the equator. Why is there a difference on a rotating perfect sphere? It's not quite connecting intuitively or physically.
mg - w' = m (v^2/r)
g' = g - (v^2/r)
I understand there's a constant radial acceleration because we're not flying off the planet. Theoretically, the difference should be 0.0337 m/s^2, but isn't because the Earth "bulges" at the equator. Why is there a difference on a rotating perfect sphere? It's not quite connecting intuitively or physically.