- #1
Andrax
- 117
- 0
This has confused me a bit
I'm typing on my phone so I can't use math symbols sorry
F(x) = 1 ; x=5
0 otherwise (x=/5)
Does lim X approaches 5 f(x) exists and = 1(f continuous at 5) ? Or does it not(because when we approach a were also in the x=/a space so there is also 1)
can someone be really kind and Prove it using epsilon?
I know you can just put alpha = any number you want since 0<epsilon always
I think I'm confusing these functions with the ones like sinx..
I'm typing on my phone so I can't use math symbols sorry
F(x) = 1 ; x=5
0 otherwise (x=/5)
Does lim X approaches 5 f(x) exists and = 1(f continuous at 5) ? Or does it not(because when we approach a were also in the x=/a space so there is also 1)
can someone be really kind and Prove it using epsilon?
I know you can just put alpha = any number you want since 0<epsilon always
I think I'm confusing these functions with the ones like sinx..
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