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4x^2-y^2+2z^2+4=0
x^2-y^2/4+z^2/2+1=0
-x^2+y^2/4-z^2/2=1
In the xy trace -x^2+y^2/4=1+k^2/2 taking k=0 will yield the hyperbola but what affect will z have on the resulting surface as it tends to +- infinity
It appears to me that as z to +- infinity the hyperbola in the xy plane becomes wider and this is not the case in the graph
x^2-y^2/4+z^2/2+1=0
-x^2+y^2/4-z^2/2=1
In the xy trace -x^2+y^2/4=1+k^2/2 taking k=0 will yield the hyperbola but what affect will z have on the resulting surface as it tends to +- infinity
It appears to me that as z to +- infinity the hyperbola in the xy plane becomes wider and this is not the case in the graph
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