- #1
gillgill
- 128
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does -e^(-infinity) equals 0?
The value of -e^(-infinity) is equal to 0.
No, -e^(-infinity) cannot be simplified to a different value as it approaches 0 in the limit as infinity increases.
Yes, as the input of -e^x approaches infinity, the output approaches 0, giving -e^(-infinity) a limit of 0.
The graph of -e^x approaches 0 as x approaches infinity, meaning it approaches -e^(-infinity) from the positive side on the y-axis.
Yes, -e^(-infinity) is an indeterminate form as it cannot be evaluated without knowing the context of the function and its limit.